The <span>flow of how a cold pack works on a sprained ankle is based on the second law of thermodynamics which states that energy will flow from a higher to a lower temperature. So your body heat will flow to the cold pack in which you will feel the coldness of the pack.</span>
Answer:
7.5 cm
Explanation:
In the figure we can see a sketch of the problem. We know that at the bottom of the U-shaped tube the pressure is equal in both branches. Defining
Ethyl alcohol density and
Glycerin density , we can write:
![\rho_A\times g \times h_1 + \rho_G \times g \times h_2 = \rho_G \times g \times h_3](https://tex.z-dn.net/?f=%20%5Crho_A%5Ctimes%20g%20%5Ctimes%20h_1%20%2B%20%5Crho_G%20%5Ctimes%20g%20%5Ctimes%20h_2%20%3D%20%5Crho_G%20%5Ctimes%20g%20%5Ctimes%20h_3%20)
Simplifying:
![\rho_A\times h_1 = \rho_G \times (h_3 - h_2) (1)](https://tex.z-dn.net/?f=%20%5Crho_A%5Ctimes%20h_1%20%3D%20%5Crho_G%20%5Ctimes%20%28h_3%20-%20h_2%29%20%281%29%20)
On the other hand:
![h_1 + h_2 = \Delta h + h_3](https://tex.z-dn.net/?f=%20h_1%20%2B%20h_2%20%3D%20%5CDelta%20h%20%2B%20h_3%20)
Rearranging:
![h_1 - \Delta h = h_3 - h_2 (2)](https://tex.z-dn.net/?f=%20h_1%20-%20%5CDelta%20h%20%3D%20h_3%20-%20h_2%20%282%29%20)
Replacing (2) in (1):
![\rho_A\times h_1 = \rho_G \times (h_1 - \Delta h)](https://tex.z-dn.net/?f=%20%5Crho_A%5Ctimes%20h_1%20%3D%20%5Crho_G%20%5Ctimes%20%28h_1%20-%20%5CDelta%20h%29%20)
Rearranging:
![\frac{h_1 \times (\rho_A - \rho_G)}{- \rho_G} = \Delta h](https://tex.z-dn.net/?f=%20%5Cfrac%7Bh_1%20%5Ctimes%20%28%5Crho_A%20-%20%5Crho_G%29%7D%7B-%20%5Crho_G%7D%20%3D%20%5CDelta%20h%20)
Data:
![h_1 = 20 cm; \rho_A = 0.789 \frac{g}{cm^3}; \rho_G = 1.26 \frac{g}{cm^3}](https://tex.z-dn.net/?f=%20h_1%20%3D%2020%20cm%3B%20%5Crho_A%20%3D%200.789%20%5Cfrac%7Bg%7D%7Bcm%5E3%7D%3B%20%5Crho_G%20%3D%201.26%20%5Cfrac%7Bg%7D%7Bcm%5E3%7D%20)
![\frac{20 cm \times (0.789 - 1.26) \frac{g}{cm^3}}{- 1.26\frac{g}{cm^3}} = \Delta h](https://tex.z-dn.net/?f=%20%5Cfrac%7B20%20cm%20%5Ctimes%20%280.789%20-%201.26%29%20%5Cfrac%7Bg%7D%7Bcm%5E3%7D%7D%7B-%201.26%5Cfrac%7Bg%7D%7Bcm%5E3%7D%7D%20%20%3D%20%5CDelta%20h%20)
![7.5 cm = \Delta h](https://tex.z-dn.net/?f=%207.5%20cm%20%3D%20%20%5CDelta%20h%20)
False
Energy in the form of motion is kinetic energy
Stored energy is called potential energy
Answer:
a) that laser 1 has the first interference closer to the central maximum
c) Δy = 0.64 m
Explanation:
The interference phenomenon is described by the expression
d sin θ = m λ
Where d is the separation of the slits, λ the wavelength and m an integer that indicates the order of interference
For the separation of the lines we use trigonometry
tan θ = sin θ / cos θ = y / x
In interference experiments the angle is very small
tan θ = sin θ = y / x
d y / x = m λ
a) and b) We apply the equation to the first laser
λ = d / 20
d y / x = m d / 20
y = m x / 20
y = 1 4.80 / 20
y = 0.24 m
The second laser
λ = d / 15
d y / x = m d / 15
y = m x / 15
y = 0.32 m
We can see that laser 1 has the first interference closer to the central maximum
c) laser 1
They ask us for the second maximum m = 2
y₂ = 2 4.8 / 20
y₂ = 0.48 m
For laser 2 they ask us for the third minimum m = 3
In this case to have a minimum we must add half wavelength
y₃ = (m + ½) x / 15
m = 3
y₃ = (3 + ½) 4.8 / 15
y₃ = 1.12 m
Δy = 1.12 - 0.48
Δy = 0.64 m