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mina [271]
2 years ago
10

Why do you think a “reliable, scholarly” source is always stressed in academic writing?

Physics
1 answer:
Anvisha [2.4K]2 years ago
4 0

Answer:

PLS MARK ME AS BRAINLIEST

Explanation:

The need for reference of reliable scholarly source in academic writing (i.e. project) is to provide guide needed to confirm the writing of the scholar and to ascertain the writing are clear of plagiarism.

In academic writing, writers are required to state out the list of sources of information because:

1)To confirm authenticity of the writing

2)To prevent future plagiarism claim from the scholar.

3)To provide guide on how to trace the scholar writing

4)To complete the requirement of good academics writing

In conclusion, providing reliable scholarly source is the backbone of writing a perfect academics article, journal inclusive.

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Which word in the sentence is a helping verb Jamie could probably repair his bike by himself
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Helping verbs come before the main verb, the main verb in the sentence is repair therefor the helping verb would be could.
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How can u tell matched forces act on objects?
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Determine the mechanical energy of this object: a 2-kg pendulum has a speed of 1 m/s at a height of 1/2 meter.
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3 0
3 years ago
Read 2 more answers
To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
iren [92.7K]

Answer:

372.3 J/^{\circ}C

Explanation:

First of all, we need to calculate the total energy supplied to the calorimeter.

We know that:

V = 3.6 V is the voltage applied

I = 2.6 A is the current

So, the power delivered is

P=VI=(3.6)(2.6)=9.36 W

Then, this power is delivered for a time of

t = 350 s

Therefore, the energy supplied is

E=Pt=(9.36)(350)=3276 J

Finally, the change in temperature of an object is related to the energy supplied by

E=C\Delta T

where in this problem:

E = 3276 J is the energy supplied

C is the heat capacity of the object

\Delta T =29.1^{\circ}-20.3^{\circ}=8.8^{\circ}C is the change in temperature

Solving for C, we find:

C=\frac{E}{\Delta T}=\frac{3276}{8.8}=372.3 J/^{\circ}C

5 0
3 years ago
What does the slope of a distance-time graph indicate?
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