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olga_2 [115]
3 years ago
13

What is the equivalent volume occupied by three millimeters of water?

Chemistry
1 answer:
natka813 [3]3 years ago
6 0

Answer:

three cubic centimeters  

Explanation:

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What are 3 Properties of Convalent electrons
yKpoI14uk [10]
Do not ionize in solutions
Poor conductors of electricity/heat
Low melting/boiling points
gases or liquids at room temperature
4 0
3 years ago
Nitrogen - 14.0067
alina1380 [7]

Answer:

potasium to erbium

Explanation:

3 0
3 years ago
If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was
Andru [333]

Answer:

pH = 2.46

Explanation:

Hello there!

In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

n_{acid}=n_{base}=n_{salt}

Whereas the moles of the salt are computed as shown below:

n_{salt}=0.021L*0.68mol/L=0.01428mol

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

[salt]=0.01428mol/0.0276L=0.517M

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

C_6H_5NH_3^++H_2O\rightleftharpoons  C_6H_5NH_2+H_3O^+

Whose equilibrium expression is:

Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

2.326x10^{-5}=\frac{x^2}{0.517M}

Whereas x is:

x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

pH=-log(3.47x10^{-3})\\\\pH=2.46

Regards!

6 0
3 years ago
How an ionic compound made up of charged particles can be electrically neutral
finlep [7]

Answer:

Explanation:

Ionic compounds are electrically neutral because the charges of the cations and anions that make up the compound cancel each other out. In the case of salt for example, sodium has a charge of positive one, and chloride has a charge of negative one. Together, they neutralize the compound.

5 0
3 years ago
If 56 grams of notrogen are used up by the reaction, how many grams of amonia will be produced? 1N2+3H2--> 2NH3
djverab [1.8K]
1 mole of N2 produces 2 moles of NH3
OR...
14 x 2 grams of N2 produces 2(14 +3) grams of NH3
1 gram of N2 produces 34/28 grams of NH3
therefore, 56 grams produce (34/28 )x 56 =68 grams of NH3 

the answer thus would be 68 grams of NH3
5 0
3 years ago
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