Answer:
0!
Explanation:
- You need to search your pKa values for Asn (2.14, 8.75), Gly (2.35, 9.78) and Leu(2.33, 9.74), the first value corresponding to -COOH, the second to -NH3 (a third value would correspond to an R group, but in this case that does not apply), and we'll build a table to find the charges for your possible dissociated groups at indicated pH (7), we need to remember that having a pKa lower than the pH will give us a negative charge, having a pKa bigger than pH will give us a positive charge:
-COOH -NH3
pH 7------------------------------------------------------
Asn - +
Gly - +
Leu - +
- Now that we have our table we'll sketch our peptide's structure:
<em>HN-Asn-Gly-Leu-COOH</em>
This will allow us to see what groups will be free to react to the pH's value, and which groups are not reacting to pH because are forming the bond between amino acids. In this particular example only -NH group in Ans and -COOH in Leu are exposed to pH, we'll look for these charges in the table and add them to find the net charge:
+1 (HN-Asn)
-1 (Leu-COOH)
=0
The net charge is 0!
I hope you find this information useful and interesting! Good luck!
Answer:
The answer is freezing (Option B)
Explanation:
To begin with, it is important to note that lava flowing from Hawaiian volcanoes are not sticky but very runny. They cool down or freeze after flowing a long way.
Since the lava is not sticky (because it is not thick), it means they are thin and prone to freezing or cooling immediately when the flow stops. Upon freezing, the lava forms crystal rocks (shiny in texture and gray in color) that are not big.
Answer:
![\boxed {\boxed {\sf Ionic \ bond}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20Ionic%20%5C%20bond%7D%7D)
Explanation:
First, let's look at the Periodic Table.
We see that aluminum is a metal, while oxygen is a non-metal.
Now, let's recall three types of bonds
- Ionic: typically forms between a metal and a non-metal
- Covalent: usually forms between non-metals
- Metallic: tends to form with metals
Since we have a metal (Al) and a non-metal (O), aluminum oxide must have an <u>ionic bond.</u>
Answer:
e. Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g)
Explanation:
All the following are oxidation–reduction reactions except:________
a. H₂(g) + F₂(g) → 2HF(g). Redox. H is oxidized and F is reduced.
b. Ca(s) + H₂(g) → CaH₂(s). Redox. Ca is oxidized and H is reduced.
c. 2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g). Redox. K is oxidized and H is reduced.
d. 6Li(s) + N₂(g) → 2Li₃N(s). Redox. Li is oxidized and N is reduced.
e. Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g). Not redox. All the elements have the same oxidation number