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3 years ago

11

A boy pulls a wagon with an applied force of 40 N on frictionless surface. If the mass of the wagon is 13kg, what is the acceler

ation of the wagon?

1 answer:

Gekata [30.6K]3 years ago

7 0

Answer:

3.1 m/s²

Explanation:

Apply Newton's second law:

∑F = ma

40 N = (13 kg) a

a ≈ 3.1 m/s²

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If the value of static friction for a couch is 400N, what could be a possible value of its kinetic friction? *

Dafna11 [192]

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As we know that maximum value of static friction on the rough surface is known as limiting friction and the formula of this limiting friction is known as

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now when object is sliding on the rough surface then the friction force on that surface is known as kinetic friction and the formula of kinetic friction is known as

$F_k = \mu_k N$

now we know that

$\mu_k < \mu_s$

so here value of limiting static friction force is always more than kinetic friction

also we know that

initially when body is at rest then static friction value will lie from 0 N to maximum limiting friction

and hence kinetic friction may be greater than static friction or if the static friction is maximum limiting friction then kinetic friction is smaller than static friction

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Answer:

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Mass of satellite, m

orbit radius of first, r1 = r

orbit radius of second, r2 = 2r

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Where v be the orbital velocity, which is given by

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So, the centripetal force is given by

$F= \frac{mgr}}{r}}=mg$

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So, the centripetal force

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