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kotegsom [21]
2 years ago
9

Which option identifies the type of device the engineer will develop in the following scenario?

Engineering
2 answers:
Monica [59]2 years ago
7 0

Answer:

Valve

Explanation:

Valves control the flow of a fluid

a "Float valve" or an electric valve controlled by a "liquid/gas" switch would be perfect

Stells [14]2 years ago
4 0
It would be actuator
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An electrochemical cell is composed of pure nickel and pure iron electrodes immersed in solutions of their divalent ions. If the
xenn [34]

Answer:C  0.12 V

Explanation:

Given

Concentration of Fe^{2+} M_1=0.40 M

Concentration of Ni^{2+} M_2=0.002 M

Standard Potential for Ni and Fe are V_2=-0.25 V  and V_1=-0.44 V

\Delta V=V_2-V_1-\frac{0.0592}{2}\log (\frac{M_1}{M_2})

\Delta V=-0.25-(-0.44)-\frac{0.0592}{2}\log (\frac{0.4}{0.002})

\Delta V=0.12\ V

7 0
3 years ago
A cylindrical tank is required to contain a gage pressure 520 kPa . The tank is to be made of A516 grade 60 steel with a maximum
enot [183]

Answer:

t= 4.5 mm

Explanation:

Given that

P = 520 KPa ( gauge)

Maximum allowable normal stress ,σ= 150

d= 2.6 m

Wall thickness = t

The normal stress for pressure vessel given as

\sigma=\dfrac{Pd}{2t}               ( hoop stress)

We always take maximum stress for safe design.

\sigma=\dfrac{Pd}{2t}

Now by putting the values

150\times 1000=\dfrac{520\times 2.6}{2t}

t= 4.5 mm

So the minimum thickness, t, of the wall is 4.5 mm

4 0
3 years ago
Can someone help me plz!!
pogonyaev
It has to do with mechanical engineering
6 0
2 years ago
Air enters a compressor steadily at the ambient conditions of 100 kPa and 22°C and leaves at 800 kPa. Heat is lost from the comp
telo118 [61]

Answer:

a) 358.8K

b) 181.1 kJ/kg.K

c) 0.0068 kJ/kg.K

Explanation:

Given:

P1 = 100kPa

P2= 800kPa

T1 = 22°C = 22+273 = 295K

q_out = 120 kJ/kg

∆S_air = 0.40 kJ/kg.k

T2 =??

a) Using the formula for change in entropy of air, we have:

∆S_air = c_p In \frac{T_2}{T_1} - Rln \frac{P_2}{P_1}

Let's take gas constant, Cp= 1.005 kJ/kg.K and R = 0.287 kJ/kg.K

Solving, we have:

[/tex] -0.40= (1.005)ln\frac{T_2}{295} ln\frac{800}{100}[/tex]

-0.40= 1.005(ln T_2 - 5.68697)- 0.5968

Solving for T2 we have:

T_2 = 5.8828

Taking the exponential on the equation (both sides), we have:

[/tex] T_2 = e^5^.^8^8^2^8 = 358.8K[/tex]

b) Work input to compressor:

w_in = c_p(T_2 - T_1)+q_out

w_in = 1.005(358.8 - 295)+120

= 184.1 kJ/kg

c) Entropy genered during this process, we use the expression;

Egen = ∆Eair + ∆Es

Where; Egen = generated entropy

∆Eair = Entropy change of air in compressor

∆Es = Entropy change in surrounding.

We need to first find ∆Es, since it is unknown.

Therefore ∆Es = \frac{q_out}{T_1}

\frac{120kJ/kg.k}{295K}

∆Es = 0.4068kJ/kg.k

Hence, entropy generated, Egen will be calculated as:

= -0.40 kJ/kg.K + 0.40608kJ/kg.K

= 0.0068kJ/kg.k

3 0
3 years ago
What steps would you take to design an improved toothpaste container?
algol [13]

Answer:

A. Identify the need, recognize limitations of current toothpaste containers, and then brainstorm ideas on how to improve the existing

Explanation:

To design an improved toothpaste container, we must identify the needs of the customer, one of the major need is to make the container attractive to the sight. This is the first thing that will prompt a customer to wanting to buy the product (The reflectance/appearance).

Then recognize the limitation of the current design, what needed change. This will help in determining what is needed to be included and what should be removed based on identified customers need.

The last step is to brainstorm ideas on how to improve the existing designs. Get ideas from other colleagues because there is a saying that two heads are better than one. This will help in coming to a reasonable conclusion on the new design after taking careful consideration of people's opinion.

7 0
3 years ago
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