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2 years ago

Which option identifies the type of device the engineer will develop in the following scenario?

Engineering

2 answers:

Monica [59]2 years ago

7 0

Answer:

Valve

Explanation:

Valves control the flow of a fluid

a "Float valve" or an electric valve controlled by a "liquid/gas" switch would be perfect

Stells [14]2 years ago

4 0

It would be actuator

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3 years ago

You gently place several steel needles on the free surface of the water in a large tank. The needles come in two lengths: some a

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3 years ago

List two ways you can make an informal survey

solniwko [45]

The two ways you can use to make an informal survey are:

make field observations
interview people using informal unstructured techniques

<h3>What are informal surveys?</h3>

In informal surveys can be regarded as a type of survey that can be made by the researcher by going to the field themselves and this can be done by using different methods or ways.

For instance, the researcher can go out to interview people that can give the data that is needed about the research such as informally asking them questions, unstructured techniques can also be used to solve critical issues.

learn more about survey at: brainly.com/question/6947486

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2 years ago

Read 2 more answers

A hair dryer is basically a duct of constant diameter in which a few layers of electric resistors are placed. A small fan pulls

Inessa05 [86]

Answer:

the percent increase in the velocity of air is 25.65%

Explanation:

Hello!

The first thing we must consider to solve this problem is the continuity equation that states that the amount of mass flow that enters a system is the same as what should come out.

m1=m2

Now remember that mass flow is given by the product of density, cross-sectional area and velocity

(α1)(V1)(A1)=(α2)(V2)(A2)

where

α=density

V=velocity

A=area

Now we can assume that the input and output areas are equal

(α1)(V1)=(α2)(V2)

$\frac{V2}{V1} =\frac{\alpha1 }{\alpha 2}$

Now we can use the equation that defines the percentage of increase, in this case for speed

$i=(\frac{V2}{V1} -1) 100$

Now we use the equation obtained in the previous step, and replace values

$i=(\frac{\alpha1 }{\alpha 2} -1) 100\\i=(\frac{1.2}{0.955} -1) 100=25.65$

the percent increase in the velocity of air is 25.65%

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3 years ago

If OSHA determines that an employer's response to a non-formal complaint is adequate, what options does the employee filing the

Anuta_ua [19.1K]

Fill it out without telling ur employer as that may cause backlash and have an osha certified employee come check out ur work or job site

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3 years ago