All categories

3 years ago

Which option identifies the type of device the engineer will develop in the following scenario?

Engineering

2 answers:

Monica [59]3 years ago

7 0

Answer:

Valve

Explanation:

Valves control the flow of a fluid

a "Float valve" or an electric valve controlled by a "liquid/gas" switch would be perfect

Stells [14]3 years ago

4 0

It would be actuator

You might be interested in

A small submarine has a triangular stabilizing fin on its stern. The fin is 1 ft tall and 2 ft long. The water temperature where

Arturiano [62]

Answer:

$\mathbf{F_D \approx 1.071 \ lbf}$

Explanation:

Given that:

The height of a triangular stabilizing fin on its stern is 1 ft tall

and it length is 2 ft long.

Temperature = 60 °F

The objective is to determine the drag on the fin when the submarine is traveling at a speed of 2.5 ft/s.

From these information given; we can have a diagrammatic representation describing how the triangular stabilizing fin looks like as we resolve them into horizontal and vertical component.

The diagram can be found in the attached file below.

If we recall ,we know that;

Kinematic viscosity v = $1.2075 \times 10^{-5} \ ft^2/s$

the density of water ρ = 62.36 lb /ft³

$Re_{max} = \dfrac{Ux}{v}$

$Re_{max} = \dfrac{2.5 \ ft/s \times 2 \ ft }{1.2075 \times 10 ^{-5} \ ft^2/s}$

$Re_{max} = 414078.6749$

$Re_{max} = 4.14 \times 10^5$ which is less than < 5.0 × 10⁵

Now; For laminar flow; the drag on the fin when the submarine is traveling at 2.5 ft/s can be determined by using the expression:

$dF_D = (\dfrac{0.664 \times \rho \times U^2 (2-x) dy}{\sqrt{Re_x}})^2$

where;

$(2-x) dy$ = strip area

$Re_x = \dfrac{2.5(2-x)}{1.2075 \times 10 ^{-5}}$

Therefore;

$dF_D = (\dfrac{0.664 \times 62.36 \times 2.5^2 (2-x) dy}{\sqrt{ \dfrac{2.5(2-x)}{1.2075 \times 10 ^{-5}}}})$

$dF_D = 1.136 \times(2-x)^{1/2} \ dy$

Let note that y = 0.5x from what we have in the diagram,

so , x = y/0.5

By applying the rule of integration on both sides, we have:

$\int\limits \ dF_D = \int\limits^1_0 \ 1.136 \times(2-\dfrac{y}{0.5})^{1/2} \ dy$

$\int\limits \ dF_D = \int\limits^1_0 \ 1.136 \times(2-2y)^{1/2} \ dy$

Let U = (2-2y)

-2dy = du

dy = -du/2

$F_D = \int\limits^0_2 \ 1.136 \times(U)^{1/2} \ \dfrac{du}{-2}$

$F_D = - \dfrac{1.136}{2} \int\limits^0_2 \ U^{1/2} \ du$

$F_D = -0.568 [ \dfrac{\frac{1}{2}U^{ \frac{1}{2}+1 } }{\frac{1}{2}+1}]^0__2$

$F_D = -0.568 [ \dfrac{2}{3}U^{\frac{3}{2} } ] ^0__2$

$F_D = -0.568 [0 - \dfrac{2}{3}(2)^{\frac{3}{2} } ]$

$F_D = -0.568 [- \dfrac{2}{3} (2.828427125)} ]$

$F_D = 1.071031071 \ lbf$

$\mathbf{F_D \approx 1.071 \ lbf}$

8 0

3 years ago

Can I have free money? I want to get a new pc

GREYUIT [131]

Answer:

NO!

Explanation:

6 0

3 years ago

Read 2 more answers

A piston–cylinder assembly contains air, initially at 2 bar, 300 K, and a volume of 2 m3. The air undergoes a process to a state

Harman [31]

Work, W = 277.269kJ

Internal energy, Q = 277.269kJ

Explanation:

Given-

Pressure, P1 = 2 bar

Temperature, T1 = 300K

Volume, V1 = 2m³

P2 = 1 bar

PV = constant

Let,

mass in kg be m

Work in kJ be W

Heat transfer in kJ be Q

R' = 8.314 kJ/kmolK

Mass of air, Mair = 28.97 kg/kmol

R = 0.289 kJ/kgK

We know,

PV = mRT

$m = \frac{P_1V_1}{RT_1}$

m = 5.65kg

To calculate V₂:

PV = constant = P₁V₁ = P₂V₂

P₁V₁ = P₂V₂

$V_2 = \frac{P_1V_1}{P_2}$

V₂ = 4m³

To calculate the work:

P₁V₁ = C

P₁ = C/ V₁

$W = \int\limits^V_V {pdV} \,$

where limit is V₁ to V₂

$W = \int\limits^V_V {\frac{c}{v} } \, dV \\\\W = C\int\limits^V_V {v^-^1} \, dV\\ \\W = P_1V_1 (ln\frac{V_2}{V_1} ) \\\\W = (2 bar) (2m^3) (ln\frac{4m^3}{2m^3}) (\frac{10^5 N/m^2}{1 bar}) \\\\W = 277.259kJ$

To calculate heat transfer:

Q - W = Δu

Q - W = m (u₂ - u₁)

Q = W + m (u₂ - u₁)

Q = W + m X cv X (T₂ - T₁)

Since, T₁ ≈ T₂

There is no change of internal energy.

W = Q

Q = 277.269kJ

6 0

3 years ago

The speed of ac motors is primarily determined by which two factors?

maw [93]

The two factors used to determine the speed of ac motors are the frequency of the power supply and the number of poles in the motor winding.

Explanation:

The frequency of the power supply and the number of poles of the machine states the synchronous speed.

The poles combined with ac line frequency determines the no-load revolutions per minute of the monitor. So all four-pole motors will run at same speed under no-load conditions, then all six-pole motors will run at the same speed.

The speed of the induction motor depends on stator frequency "s ". By varying the stator voltage and constant supply frequency the speed can be controlled. The two main components of the electric motor are stator and rotor.

3 0

3 years ago

Substance Specific Heat (cal/g°C) Specific Heat (J/g°C) water 1.00 4.18 steam 0.96 4.02 alcohol 0.59 2.47 ice 0.50 2.09 wood 0.4

Jobisdone [24]

Answer:

C) 43,2°C

Explanation:

Sensible heat is the amount of thermal energy that is required to change the temperature of an object, the equation for calculating the heat change is given by:

Q=msΔT

where:

Q, heat that has been absorbed or realeased by the substance [J]
m, mass of the substance [g]
s, specific heat capacity [J/g°C]
ΔT, changes in the substance temperature [°C]

To solve the problem, we clear ΔT of the equation and then replace our data:

Q=890 [J],

m=16,6 [g],

s=2,74 [J/g°C]

Q=msΔT.......................ΔT=Q/ms

Δ $T=\frac{890 J}{16,6g*2,47\frac{J}{gC}}=21,7$ °C

As:

ΔT=Tfinal-Tinitial

Tfinal=ΔT+Tinitial

Tfinal=21,7+21,5=43,2°C

The final temperature of the ethanol is 43,2°C.

4 0

4 years ago