Question

A disk brake has two pads which cover 45 degrees of the disk. The outside radius is 6.0 inch and the inside radius is 4.0 inch. Assume a coefficient of friction of 0.4, and a max pressure, pa=100 psi. a) Find the force required to apply one pad. b) Find the torque capacity for both pads.

Answer 1

Answer:

f = 628.32 lb

t = 2513.28 lb-inc

Explanation:

given data:

θ = 45°

outside radius = 6 inch

inside radius = 4 inch

coefficient of friction = 0.4

max pressure = 100 psi

a) determine force required for applying one pad

f =    $\frac{\theta }{360}* 2\pi *p_{max}*r_{i}(r_{o}-r_{i})$

f = $\frac{45 }{360}* 2\pi *100*4(6-4)$

f = 628.32 lb

b) torque capacity (t)

t = $\mu *f*r_{average}^{}$

t = 0.4 *628.32*5

torque = 1256.64 lb-inc

for both pad = 2 * 1256.64 =2513.28 lb-inc