Answer:
μ = 0.136
Explanation:
given,
velocity of the car = 20 m/s
radius of the track = 300 m
mass of the car = 2000 kg
centrifugal force


F c = 2666. 67 N
F f= μ N
F f = μ m g
2666.67 = μ × 2000 × 9.8
μ = 0.136
so, the minimum coefficient of friction between road surface and car tyre is equal to μ = 0.136
Answer:
I think that the answer is the Chinese
Explanation:
Answer:
Super critical
1.2 m
Explanation:
Q = Flow rate = 
w = Width = 3 m
d = Depth = 90 cm = 0.9 m
A = Area = wd
v = Velocity
g = Acceleration due to gravity = 

Froude number is given by

Since
the flow is super critical.
Flow is critical when 
Depth is given by

The depth of the channel will be 1.2 m for critical flow.
Answer:
The duration of the consolidation process for the same clay is 32 min
Explanation:
for clay 1:
t1=0
H1=thickness=2 cm
for the clay 2:
t2=?
H2=2 cm
The time factor is equal to:

where Cv is the coefficient of consolidation

if Cv is constant, we have:

Clearing t2:
t2=32 min