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JulijaS [17]
3 years ago
11

A super conductor performs best at

Chemistry
1 answer:
Anastaziya [24]3 years ago
4 0

A superconductor performs best at very cold temperatures.


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How many moles are in 68.16 grams of NH3 ?
seropon [69]

Answer:

4.002 mol is in 68.16 grams of NH3

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soaps do not work well in hard waters. But they can still be effected it large quantities of soap are added to water. Explain wh
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They can still be effected it large quantities of soap are added to water

because more soap eliminates the effect the minerals in hard water has on

its cleaning capacity.

Hard water contains minerals such as

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They reduce the cleaning capacity of the soap. This is why soft water is

preferably used as it doesn't contain these minerals.

When more soap is added, the effect of the minerals reduces thereby

bringing about very little or no effect on the cleaning capacity of the soap.

Read more about Soap here brainly.com/question/1473301

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Your sick puppy is diagnosed with roundworms. They grow inside of the puppy. What type of symbiotic relationship do the puppy an
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3 years ago
Consider the reaction: CaCO3(s) à CaO(s) + CO2(g)
Vsevolod [243]

Answer:

131.5 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

First, we will calculate the standard enthalpy of the reaction (ΔH°).

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g) ) - 1 mol × ΔH°f(CaCO₃(s) )

ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)

ΔH° = 179.2 kJ

Then, we calculate the standard entropy of the reaction (ΔS°).

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g) ) - 1 mol × S°(CaCO₃(s) )

ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)

ΔS° = 160.2 J/K = 0.1602 kJ/K

Finally, we calculate the standard Gibbs free energy of the reaction at T = 25°C = 298 K.

ΔG° = ΔH° - T × ΔS°

ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K

ΔG° = 131.5 kJ

6 0
3 years ago
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