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Stells [14]
3 years ago
13

What do cilia and flagella have in common?

Chemistry
1 answer:
12345 [234]3 years ago
8 0

Answer:B

Explanation:

You might be interested in
What do carbon, hydrogen, and oxygen atoms have in common?
horsena [70]

Answer:

electrons located outside the nucleus

Explanation:

electrons are said to be located outside the nucleus of an atom and are in orbit around the nucleus.

according to Bohr in 1913.

6 0
2 years ago
Mercury’s atomic emission spectrum is shown below. Estimate the wavelength of the orange line. What is its frequency? What is th
lions [1.4K]

The wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

<em>"Your question is not complete, it seems to be missing the diagram of the emission spectrum"</em>

the diagram of the emission spectrum has been added.

<em>From the given</em><em> chart;</em>

The wavelength of the atomic emission corresponding to the orange line is 610 nm = 610 x 10⁻⁹ m

The frequency of this emission is calculated as follows;

c = fλ

where;

  • <em>c is the speed of light = 3 x 10⁸ m/s</em>
  • <em>f is the frequency of the wave</em>
  • <em>λ is the wavelength</em>

f = \frac{c}{\lambda } \\\\f = \frac{3\times 10^8}{610 \times 10^{-9}} \\\\f = 4.92 \times 10^{14} \ Hz

The energy of the emitted photon corresponding to the orange line is calculated as follows;

E = hf

where;

  • <em>h is Planck's constant = 6.626 x 10⁻³⁴ Js</em>

<em />

E = (6.626 x 10⁻³⁴) x (4.92 x 10¹⁴)

E = 3.26 x 10⁻¹⁹ J.

Thus, the wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

Learn more here:brainly.com/question/15962928

6 0
2 years ago
When you transferred the hot metal from the boiling water and into the calorimeter (coffee cup), if the thermometer touched the
sergey [27]

When you transferred the hot metal from the boiling water and into the calorimeter,  The effect will be

  • Change in temp is positive
  • Temp of metal V, dT=-ve
  • No change occurs in the specific heat of metal

This is further explained below.

<h3>What is the Specific heat of the metal?</h3>

a )Since the metal of the cup is hot and the water inside is cold, the water's temperature will rise as heat is transferred from the metal to the liquid.

Change in temp is positive

b)

Due to (a), heat is lost from the food to the water in the cup, lowering the metal's temperature.

Temp of metal V, dT=-ve

c)

No change occurs in the specific heat of metal because of its constant property.

Read more about Temperature

brainly.com/question/13439286

#SPJ1

7 0
2 years ago
Read 2 more answers
A sample of water vapor has a volume of 3.15 L, a pressure of 2.40 atm, and a temperature of 325 K. What is the new temperature,
lara31 [8.8K]

Answer:

The answer to your question is:   T2 = 235.44 °K

Explanation:

Data

V1 = 3.15 L                    V2 = 2.78 L

P1 = 2.40 atm               P2 = 1.97 atm

T1 = 325°K                    T2 = ?

Formula

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Process

            T2 = (P2V2T1) / (P1V1)

            T2 = (1.97x 2.78x 325) / (2.40 x 3.15)

            T2 = 1779.895 / 7.56

            T2 = 235.44 °K

4 0
3 years ago
To find the volume of a ring, the water displacement method was used.
ohaa [14]

Answer:

4 cm³?

Explanation:

68-64

4 0
3 years ago
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