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Jobisdone [24]
3 years ago
6

A ball of mass 8 kg falls from rest from a height of 100 m. Neglecting air resistance,calculate its kinetic energy after falling

a distance of 30 m.
Physics
2 answers:
astra-53 [7]3 years ago
4 0
As an object falls from rest, its gravitational energy is converted to kinetic energy

G.P.E = K.E = mgh

K.E = (80 Kg)(9.8 m/s²)(30 m)

K.E. = 23,520 J
xxMikexx [17]3 years ago
3 0
At h=100m,
ME = KE + PE
ME = 1/2mv^2 + mgh
ME = 1/2m(0)^2 + mgh     Because the ball has no speed at first
ME = mgh = 8 x 9.8 x 100 = 7840 J

At h=70m   (100m-30m)
ME = KE + PE
7840 J = KE + mgh
KE = 7840 J - mgh = 7840 - 8 x 9.8 x 70
KE = 7840 - 5488
KE = 2352 J

Hope this helps

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En la siguiente expresión matemáticas w=mg el peso w con relación a se relaciona con la masa m en una proporción
s2008m [1.1K]

Answer:

a) Directamente proporcional

Explanation:

El peso se puede definir como la fuerza que actúa sobre un cuerpo o un objeto como resultado de la gravedad.

Matemáticamente, el peso de un objeto viene dado por la fórmula;

Peso = mg

Donde;

m es la masa del objeto.

g es la aceleración debida a la gravedad.

De la expresión matemática, podemos deducir que el valor del peso de un objeto es directamente proporcional a la masa del objeto.

Por lo tanto, un aumento en la masa de un objeto provocaría un aumento en el peso del objeto y viceversa.

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3 years ago
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4 0
3 years ago
Which requires more work, carrying a 420 N knapsack up a 200 m hill or carrying a 210 knapsack up a 400 m hill? Why?
Katen [24]

Answer:

b

Explanation:

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3 years ago
A long straight wire carries a conventional current of 0.7 A. What is the approximate magnitude of the magnetic field at a locat
vfiekz [6]

Answer:

2.64 x 10⁻⁶T

Explanation:

The magnitude of the magnetic field produced by a long straight wire carrying current is given by Biot-Savart law as follows: "The magnetic field strength is directly proportional to the current on the wire and inversely proportional to the distance from the wire". This can be written mathematically as;

B = (μ₀ I) / (2π r)                ----------------(i)

B is magnetic field

I is current through the wire

r is the distance from the wire

μ₀  is the magnetic constant = 4π x 10⁻⁷Hm⁻¹

From the question;

I = 0.7A

r = 0.053m

Substitute these values into equation (i) as follows;

B =  (4π x 10⁻⁷ x 0.7) / (2π x 0.053)

B = 2.64 x 10⁻⁶T

Therefore the approximate magnitude of the magnetic field at that location is 2.64 x 10⁻⁶T

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3 years ago
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