Answer.

The road on the hills goes upward with the increasing length of the road.That's why we make a winding roads because it reduces the allover surface inclination in every portion of the road which is suitable for driving the vehicles.

3 0

3 years ago

Estimate the average force that a baseball pitcher's hand exerts on a 0.145-kg baseball as he throws a 40-m/s pitch. Assume the

Kitty [74]

Answer:

38.67 N

Explanation:

v = Final velocity = 40 m/s

u = Initial velocity

m = Mass of ball = 0.145kg

s = Displacement of ball = 3 m

Equation of motion

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{40^2-0^2}{2\times 3}=\frac{800}{3}\ m/s^2$

F=ma

$\\\Rightarrow F=0.145\times \frac{800}{3}\\\Rightarrow F=38.67\ N$

∴ Average force that a baseball pitcher's hand exerts on the ball is 38.67 N

6 0

2 years ago

Read 2 more answers

A physics major is working to pay his college tuition by performing in a traveling carnival. He rides a motorcycle inside a holl

Semenov [28]

Answer:

a) v=23.9 m/s

b) R=2646 N

Explanation:

According to Newton's second law the net force at the top is given by

∑F=-m*ac

according to

$a_{c}=\frac{v^2}{r}$

∑F= $-m*\frac{v^2}{r}$

a).

To lose contact this means that R=0 so the final equation is

$R-m*g=-m*\frac{v^2}{r}$

$-m*g=-m*\frac{v^2}{r}$

Solve to v

$v^2=g*r$

$v=\sqrt{g*r}=\sqrt{9.8*14.6}$

$v=11.96\frac{m}{s}$

b).

v is the twice of part a so

$v=2*11.96$

$v=23.9\frac{m}{s}$

$R_{m}-m_{m}*g-m_{p}=m*\frac{v^2}{r}$

Solve to Rm

$R_{m}=m*\frac{v^2}{r}+(m_{m}+m_{p})*g$

$R_{m}=m*\frac{23.9^2}{14.6}+(40+70)*9.8$

$R_{m}=2646 N$

5 0

2 years ago