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Vitek1552 [10]
3 years ago
13

how may kilojoules of heat are required to melt a 10.0g popsicle at 0 degrees C?(assume the same properties as water)

Physics
2 answers:
yanalaym [24]3 years ago
7 0
<span>there are different machines that help measure the distance of a property for construction workers to determine where to put a foundation </span>
Nikolay [14]3 years ago
3 0
The heat of fusion for water is 334j/g 
therefore 1g of ice would require 334 x  10 j of energy which is 3.34kJ
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A piece of driftwood moves up and down as water waves pass beneath it. However, it does not move toward the shore with the waves
pantera1 [17]

Answer:

It's A

Explanation:

As the waves progress through the medium, the particles they are made of move perpendicular to the direction in which the waves move. The particles do not move with the wave. So waves transmit energy but not matter as they progress through a medium.

6 0
3 years ago
Which force can affect an object without direct physical contact?
denis-greek [22]
Gravity affet everything and it touches nothing.
Hope this helps!
8 0
3 years ago
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What role does a resistor play in an electrical circuit
kirza4 [7]

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Explanation: just did the quiz on

4 0
2 years ago
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In your physics lab you are given a 10.1-kg uniform rectangular plate with edge lengths 68.7 cm by 47.5 cm. Your lab instructor
VladimirAG [237]

Answer:

2.35 kgm^2

Explanation:

we take length 68.7 cm as x-axis and 47.5 cm as y-axis then the axis about which we have to find out moment of inertia will be z-axis.

moment of inertia about x-axis

I_x = ML^2 /3 = 10.1\times 0.4752 /3 = 0.7596 kg-m2

I_y = 10.1\times 0.6872 / 3 = 1.5889 kgm^2

by perpendicular axis theorem

I_z = I_x + I_y = 0.7596 + 1.5889 = 2.35 kgm^2

4 0
2 years ago
A weightlifter is attempting a biceps curl with a 200 n barbell. the moment arm of the barbell about the elbow joint is 40 cm. t
CaHeK987 [17]
Weight of the barbell W = 200 Ndistance of the joint is r = 40 cm = 0.4 mtorque created by the weight at the joint is                  τ = F*r                     = 200 N*0.4 m                     = 80 N.mat equilibrium condition ,    Στ = force*distance - 80 N.m = 0             F'*0.4 - 80 N.m = 0             F'*0.4 = 80          force F' = 200 N
4 0
3 years ago
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