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Goryan [66]
3 years ago
11

A 1200 kg car surrounds an 80 meter radius curve. If the coefficient of friction between the tires and the road is 0.65, what ma

ximum speed should the car have to not leave the curve to : a. 23 m / s
b. 10 mph
c. 62 km / h
d. 6.3 m / s
Physics
1 answer:
GuDViN [60]3 years ago
4 0

Answer: a) 23 m/s

Explanation: In order to solve this problem we have to consider the circular movement  where the friction force  change de direcion of the velocty to keep a circular trajectory.

By using Second Newton law, we have:

F=m*acentripeta

μ*N= m*v^2/r  where N  ( equal to mg) is the normal force and μ is the coefficient of friction. r is the redius of the trajectory.

so

the maximun speed permited to keep a circular trajectory is calculated as:

v= (μ*r*g)^1/2=(0.65*80m*9.8 m/s^2)^1/2=22.57 m/s

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x(t) = 8 cos t, x(5π/6)= 8 cos(<span>5π/6)
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An 85-kg man plans to tow a 109 000-kg airplane along a runway by pulling horizontally on a cable attached to it. Suppose that h
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Answer:

The greatest acceleration the man can give the airplane is 0.0059 m/s².

Explanation:

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a=\dfrac{ 641.41}{109000}

a=0.0059\ m/s^2

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