Labels that belong in regions marked X and Y are;
A) X: Maintains magnetic properties in the presence of another magnet
Y: Is made from magnetically hard ferromagnetic material
1) d = V*t >>>as you double the av. speed the distance become doubled.
2) after you draw the victors you will find the total displacement = 1 meter to the left.
3) V =d/t =( 8km)/(1.25hr) = 6.4km/hr
Answer:
Explanation:
We shall use Ampere's circuital law to find magnetic field at required point.
The point is outside the circumference of two given wires so whole current will be accounted for .
Ampere's circuital law
B = ∫ Bdl = μ₀ I
line integral will be over circular path of radius r = 41 cm .
Total current I = 5A -3A = 2A .
∫ Bdl = μ₀ I
2π r B = μ₀ I
2π x .41 B = 4π x 10⁻⁷ x 2
B = 2 x 10⁻⁷ x 2 / .41
= 9.75 x 10⁻⁷ T . It will be along - ve Y - direction.
