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Debora [2.8K]
4 years ago
9

A service elevator takes a load of garbage, mass 10.0 kg, from a floor of a skyscraper under construction, down to ground level,

accelerating downward at a rate of 1.2 m/s2 . Find the magnitude of the force the garbage exerts on the floor of the service elevator
Physics
1 answer:
kobusy [5.1K]4 years ago
8 0

Answer:

The magnitude of the force the garbage exerts on the floor of the service elevator is 12 N

Explanation:

Given;

mass of the garbage, m = 10.0 kg

acceleration of the elevator, a = 1.2 m/s²

The magnitude of the force the garbage exerts on the floor of the service elevator is given by;

F = ma

F = 10 x 1.2

F = 12 N

Therefore, the magnitude of the force the garbage exerts on the floor of the service elevator is 12 N

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The interstellar clouds called molecular clouds are _________.
ira [324]

Answer:

nebulas and they are the cool clouds in which stars form

Explanation:

The stars are born by chance. Fragments of matter are gathered from the cool clouds of gas and dust that float in space, the so-called nebulas. These particles are added by gravitational attraction to form a large mass.

This conglomerate, due to the effect of gravity, contracts on itself and as a consequence increases in its center, density, pressure and heat. In this way, atoms move faster and collide with each other. Under these conditions, nuclear fusion reactions soon begin. When they start the star is born.

3 0
3 years ago
a positively charged body makes contact with a body. after a while, the charged body becomes neutralised. state 3 main condition
MrRa [10]

Answer:

A body will become positively charged when some electrons will come out from the body.Thus, positive charge is due to deficiency of electrons.

5 0
3 years ago
The bus, at location A, is traveling at 30 m/s when it is shifted to neutral and allowed to
sertanlavr [38]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The velocity of the bus at B is v_B= 31.6\  m/s

Explanation:

Let's take  position B as base point .

From the diagram  height between point B and A ia mathematically evaluated as

        h_A  = 60 -55

      h_A  = 5 \ m

From the question we are told that

   The velocity at location A is  v_A = 30 m/s

       

     According the law of conservation of energy

          PE_A + KE_A = KE_B

Where PE_A is the potential energy at A which is mathematically represented as

          PE_A = mgh_A

KE_A is the kinetic energy energy at A which is mathematically represented as

            KE_A = \frac{1}{2} mv^2_A

KE_B is the  kinetic energy at A which is mathematically represented as

          KE_B = \frac{1}{2} mv_B^2

Where v_B is the velocity at location B

So

      mgh_A + \frac{1}{2} mv_A^2 = \frac{1}{2} mv_B^2

Making v_B the subject of the formula

       v_B=  \sqrt{\frac{gh_A + \frac{1}{2} v_A^2 }{0.5} }

Substituting values

       v_B=  \sqrt{\frac{(9.8 * 5) + \frac{1}{2} 30^2 }{0.5} }

        v_B= 31.6\  m/s

7 0
3 years ago
A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. What is the tangential acceleration (in m/s2) of a point on
wolverine [178]

Answer:

2.1 m/s²

Explanation:

By definition, the angular acceleration, is equal to the rate of change of the angular velocity, ω:

α = Δω / Δt (1)

By definition of the angular velocity, we can express the linear velocity, v, as follows:

v = ω*r⇒ Δv = Δω*r (2)

Replacing Δω, from (1) in (2), we get:

Δv = α*Δt*r⇒ Δv/Δt = α*r (3)

By definition of linear acceleration, we can write the following expression;

a = α*r

For a point on the edge of the wheel, the linear acceleration is tangent to the rim, and is equal to the product of the angular acceleration times the distance to the center, which for a point on the edge of the wheel, is just the radius:

⇒ a = 7 rad/sec²*0.3m = 2.1 m/s²

3 0
4 years ago
Which two statements are true? Select all that apply. Select one or more: a. A moving magnetic field creates an electric field.
omeli [17]
<span>2. An electric current in a conductor creates a magnetic field at all points in the surrounding region.
3. A permanent magnet creates a magnetic field at all points in the surrounding region.
4. A moving electric charge creates a magnetic field at all points in the surrounding region.</span>
6 0
3 years ago
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