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avanturin [10]
2 years ago
13

If you found some sandstone in an ancient river bed, which of these conditions at the time that the sandstone was formed would b

e easiest to understand?
A. what the climate was like
B. how old the particles were
C. how fast the river was flowing
D. when the particles were deposited
Physics
1 answer:
Ulleksa [173]2 years ago
8 0
I believe that the answer to this would be option C. Since sandstones are not commonly seen among river beds, the condition that would make us easier to understand as to what happened to this is how fast the river was flowing. Due to the pressure of the river, this brought other sediments with it most especially sandstones.
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aivan3 [116]

The reason for people to swim easier in salt water than fresh water is because of buoyancy

Explanation:

In fresh water there is lack of minerals and has fresh water alone. The density of fresh water is 1000 kg/m³.  Hence, in fresh water  cannot exert the suitable buoyancy for the swimmer to float easier than that of salt water.

But in Salt water due to enrichment of salts  and minerals it is found that salt water has more density than fresh water. Here the salt water offers more buoyancy to the swimmer to lift him up in the water surface and to swim faster and easier than fresh water.

It is similar to that egg floats in the salt water and sinks inside the fresh water because of its own body weight.

4 0
2 years ago
Read 2 more answers
An atom of this element would have a very easy time losing one electron to form an ionic bond with an atom of an element that wo
shepuryov [24]

Answer: potassium

Explanation: An atom of potassium would have a very easy time losing one electron to form an ionic bond with an atom of an element that would easily accept it.

8 0
3 years ago
A hammer exerts 49.8 N of force on the head (r=0.00510 m) of a nail. How much pressure does it exert on the nail?
Kisachek [45]

Answer:

609547.12 Pa ≈ 6.10×10^5 Pa

Explanation:

Step 1:

Data obtained from the question. This include the following:

Force (F) = 49.8 N

Radius (r) = 0.00510 m

Pressure (P) =..?

Step 2:

Determination of the area of the head of the nail.

The head of a nail is circular in nature. Therefore, the area is given by:

Area (A) = πr²

With the above formula we can obtain the area as follow:

Radius (r) = 0.00510 m

Area (A) =?

A = πr²

A = π x (0.00510)²

A = 8.17×10^-5 m²

Therefore the area of the head of the nail is 8.17×10^-5 m²

Step 3:

Determination of the pressure exerted by the hammer.

This is illustrated below:

Force (F) = 49.8 N

Area (A) = 8.17×10^-5 m²

Pressure (P) =..?

Pressure (P) = Force (F) /Area (A)

P = F/A

P = 49.8/8.17×10^-5

P = 609547.12 N/m²

Now, we shall convert 609547.12 N/m² to Pa.

1 N/m² = 1 Pa

Therefore, 609547.12 N/m² = 609547.12 Pa.

Therefore, the pressure exerted by the hammer on the nail is 609547.12 Pa or 6.10×10^5 Pa

8 0
3 years ago
Newton began his academic career in 1667. For how long was he a working scientist? Was he a very productive scientist?
rjkz [21]
Newton's 3 laws are...

inertia: things tend to continue to do what they are doing.

Change: to make something change you need a force to change it. the force needed = the mass times its acceleration

<span> Resistance: When you push on something, it pushes back. 

From yahoo answers
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7 0
2 years ago
A 4-79 permalloy solenoid coil needs to produce a minimum inductance of 1.1 . If the maximum allowed current is 4 , how many tur
daser333 [38]

The related concept to solve this exercise is given in the expressions that the magnetic field has both as a function of the number of loops, current and length, as well as inductance and permeability. The first expression could be given as,

The magnetic field H is given as,

H = \frac{nI}{l}

Here,

n = Number of turns of the coil

I = Current that flows in the coil

l = Length of the coil

From the above equation, the number of turns of the coil is,

n = \frac{Hl}{I}

The magnetic field is again given by,

H = \frac{B}{\mu_t}

Where the minimum inductance produced by the solenoid coil is B.

We have to obtain n, that

n = \dfrac{\frac{B}{\mu_t}l}{I}

Replacing with our values we have that,

n = \dfrac{\frac{1.1Wb/m^2 }{200000}(2m)}{4mA}

n = \dfrac{(\frac{1.1Wb/m^2 }{200000})(\frac{10^4 guass}{1Wb/m^2})(2m)}{4mA(\frac{10^{-3}A}{1mA})}

n = 27.5 \approx 28

Therefore the number of turn required is 28Truns

4 0
3 years ago
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