Answer:
Spring constant, k = 1.16 N/m
Explanation:
It is given that,
Mass of the air track, m = 0.2 kg
Time, t = 2.6 s
Let T is the time period of the spring. The expression for the time and spring constant is given by :
k = 1.16 N/m
So, the spring’s force constant is 1.16 N/m. Hence, this is the required solution.
Answer:
D
Explanation:
the man is pull the box that is the force and the box rubbing against the ground causes friction
Answer:
The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.
Explanation:
Given that,
Mass of softball = 0.220 kg
Speed = 5.5 m/s
(a). We need to calculate the velocity of the target ball
Using conservation of momentum
....(I)
The velocity approach is equal to the separation of velocity
(b). We need to calculate the mass of the target ball
Now, Put the value of v₂ in equation (I)
Hence, The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.
Answer:
Explanation:
Given that,
Magnetic field of 0.24T
B = 0.24T
Field perpendicular to plane i.e 90°
Rate of decrease of length of side of square is 5.4cm/s
dL/dt = 5.4cm/s = 0.054m/s
Since it is decreasing
Then, dL/dt = -0.054m/s
When L is 14cm, what is the EMF induced?
L = 14cm = 0.14m
EMF is give as
ε = - dΦ/dt
Where flux is given as
Φ = BA
Where A is the area of the square
A = L²
Then, Φ = BL²
Substituting this into the EMF
ε = - dΦ/dt
ε = - d(BL²)/dt
B is constant
ε = - Bd(L²)/dt
ε = -2BL dL/dr
ε = -2 × 0.24 × 0.14 × -0.054
ε = 3.63 × 10^-3 V
ε = 3.63mV
Answer: Newton's second law of motion is F = ma or force is equal to the mass the reason this applies to Newton's third law is because When the game starts, both the sides are pulling the rope and neither side is moving. The force on the rope is the same on each side This is Newton's second law of motion which equates force as mass times acceleration.
Explanation:
