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Ivanshal [37]
3 years ago
10

A purse at radius 2.10 m and a wallet at radius 3.15 m travel in uniform circular motion on the floor of a merry-go-round as the

ride turns. They are on the same radial line. At one instant, the acceleration of the purse is . At that instant and in unit-vector notation, what is the acceleration of the wallet?
Physics
1 answer:
vlada-n [284]3 years ago
5 0

Complete question is:

A purse at radius 2.10 m and a wallet at radius 3.15 m travel in uniform circular motion on the floor of a merry-go-round as the ride turns. They are on the same radial line. At one instant, the acceleration of the purse is 1.7 m/s^2 \hat i+3.20m/s^2 \hat j . At that instant and in unit-vector notation, what is the acceleration of the wallet?

Answer:

a'= 2.55 m/s^2\hat i + 4.8 m/s^2 \hat j    

Explanation:

Given: Purse is at radius, R=2.10 m

Wallet is at radius, R'=3.15 m

acceleration of the purse, a = 1.7 m/s^2 \hat i+3.20m/s^2 \hat j

a=r\omega^2

Both the purse and wallet would have same angular velocity \omega.

\sqrt \frac{a}{R}=\sqrt \frac{a'}{R'}

a'=\frac{a}{R}\times R \\ \Rightarrow a' = \frac{1.7 m/s^2 \hat i+3.20m/s^2 \hat j}{2.10 m}\times 3.15 m \\ a'= 2.55 m/s^2\hat i + 4.8 m/s^2 \hat j

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