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3 years ago

Mechanical waves form when a source of energy causes a medium to what

Physics

1 answer:

Mice21 [21]3 years ago

7 0

Answer:

Ripple in water is a surface wave. A mechanical wave is a wave that is an oscillation of matter, and therefore transfers energy through a medium. While waves can move over long distances, the movement of the medium of transmission —the material—is limited.

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Which event is an example of condensation?

Sonbull [250]

Answer:

Fog forms in a valley

Explanation: that’s the only reasonable response

5 0

4 years ago

A 9Ω resistance is cut into three equal parts and connected in parallel. Find the equivalent resistance of the combination.

sammy [17]

Answer:

the ans i 1 ohm

Explanation:

if i cut a resistor of 9 ohm into 3 equal parts then each resistor will have a resistance of 3 ohm and if they are in parallel combination the net resistance will be R

so 1/R=1/R1+1/R2+1/R3

1/R=1/3+1/3+1/3

R=1

7 0

3 years ago

A receiver catches a football on the 50.0 yard line and is tackled 5.42 seconds later on the 12 yard line. What

tester [92]

Answer:

7.01yard/sec

Explanation:

Given parameters:

Initial position = 50yard

Final position = 12yard

Time = 5.42s

Unknown:

Average speed of runner = ?

Solution:

To solve this problem;

Speed = $\frac{distance}{time}$

Distance covered = Initial position - final position = 50 - 12 = 38yards

So;

Speed = $\frac{38}{5.42}$ = 7.01yard/sec

5 0

3 years ago

A 23.0 kg child plays on a swing having support ropes that are 2.10 m long. A friend pulls her back until the ropes are 45.0 deg

Romashka [77]

Answer:

a. 139.748J

b.3.486m/s

c.zero

Explanation:

a. Given the mass of the child as 23.0kg, rope length is 2.1mand incline is 45°

Potential energy during release is calculated as: $PE=mgh$

#Find vertical difference of when the swing is at rest (2.1m) and when the child is pulled back.

Find the height when the child is pulled back:

$cos 45\textdegree=y/2.10\\\\y=1.48m$

#therefore,vertical difference is 2.1m-1.48m=0.62m

$\therefore PE=mgh\\\ \ =23.0kg\times 9.8m/s^2\times 0.62m\\\ \ =139.748J$

#Hence the potential energy during release is 139.748J

b. From a, above, we have PE=139.748J, M=23.0kg.

At the bottom, all the PE will be transferred into KE. Potential energy is calculated as:

$KE=0.5mv^2\\\\mv^2=2KE\\\\v=\sqrt{2KE/m}\\\\v=\sqrt{2\times 139.748J/23.0}\\\\v=3.486m/s$

#Hence the velocity at the bottom of the swing is 3.486m/s

c. Work is calculated as the product of force by distance.

From a, b above we have mass as 23.0kg .

-since the distance of the ropes remained constant the change in distance is zero:

$W=mgd\\=23.0\times 9.8m/s^2\times 0\\=0$

Therefore the work in the ropes is 0,zero.

8 0

3 years ago

An Olympic runner completes the 200-meter sprint in 23 seconds. What is the runnerâ€™s average speed? (Round your answer to the

Amanda [17]

The average speed of the runner is 8.7m/s.

Therefore, Option C) 8.7m/s is the correct answer.

Given the data in the question;

Distance covered; $d = 200m$

Time taken; $t = 23s$

Average speed; $s = \ ?$

Speed is the rate at which an object covers a certain distance. It is expressed as:

$s = \frac{d}{t}$

Where s is speed, d is distance and t is time taken.

We substitute our given distance into the equation

$s = \frac{200m}{23s} \\\\s = 8.6956m/s\\\\s = 8.7m/s$

The average speed of the runner is 8.7m/s

Therefore, Option C) 8.7m/s is the correct answer.

Learn more: brainly.com/question/21503615

3 0

2 years ago