Examine the diagram of the cell cycle.
2 answers:
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Answer:
5.7 m/s^2
Explanation:
First of all, we need to calculate the resultant force on the crate. We have:
- A force of +210 N in the positive direction
- The frictional force of -74 N in the opposite direction
So, the resultant force is
F = 210 N - 74 N= 136 N
So now we can apply Newton's second law to find the acceleration:
where m=24 kg is the mass of the crate. Re-arranging the equation, we get:
Answer:
The ball to hit the ground in 0.53 s.
Explanation:
Given that,
Height = 1.4 m
Time t = 0.53 s
Initial speed = 35 m/s
We need to calculate the time when the ball to hit the ground
Using equation of motion
Where, s= vertical height
u= vertical velocity
t = time
h = height
Put the value in equation
Hence, The ball to hit the ground in 0.53 s.
Answer:
D 60°
Explanation:
Using trigonometry:
- The new speed (v/2) of the particle corresponds to the hypothenuse
- The component of v/4 represents the side adjacent to the angle that we want fo find,
So we can write:
So we find the angle