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Whitepunk [10]
3 years ago
15

Select all of the answers that apply.

Physics
2 answers:
kolezko [41]3 years ago
7 0

Answer:

-law of original horizontality

-law of superposition

-law of original lateral continuity

-law of cross-cutting or intrusive relationships

Explanation:

Relative dating is the science that many scientist use to set an order, or to figure out the order in which past events happened, this is without actually invetigating the natural age of the elements, and from stratigraphy and paleontology the laws of relative dating are:

  1.    Uniformitarianism
  2.    Intrusive relationships
  3.    Cross-cutting relationships
  4.    Inclusions and components
  5.    Original horizontality
  6.    Superposition
  7.    Faunal succession
  8.    Lateral continuity
postnew [5]3 years ago
3 0
Here are the answers to the given question above.
<span>Relative dating uses laws or principles of stratigraphy and paleontology. These laws of relative dating are: 
-</span><span>law of original horizontality 
-</span><span>law of superposition 
-</span><span>law of original lateral continuity 
-</span><span>law of cross-cutting or intrusive relationships 
Hope these are the answers that you are looking for.</span>
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Objects 1 and 2 attract each other with a gravitational force of 72.0 units. If the mass of Object 1 is one-fourth the original
Black_prince [1.1K]

Answer:

New gravitational force, F' = 216 units

Explanation:

Given that,

Gravitational force between object 1 and 2, F = 72 N

The gravitational force between two objects is given by :

F=\dfrac{Gm_1m_2}{r^2}

\dfrac{Gm_1m_2}{r^2}=72............(1)

If the mass of object 1, m_1'=\dfrac{m_1}{4}

m_2'=3m_2

If the distance between objects is halved, r'=\dfrac{r}{2}

Let new gravitational force is F'. It is changed to :

F=\dfrac{Gm'_1m'_2}{r'^2}

F'=\dfrac{G\times \dfrac{m_1}{4}\times 3m_2}{(\dfrac{r}{2})^2}

F'=3\times \dfrac{Gm_1m_2}{r^2}

F'=3\times F

F'=3\times 72

F' = 216 units

So, the  new gravitational force will be 216 units.

6 0
3 years ago
If you could see the electric field coming off a proton you would notice that electric field lines are what?
Readme [11.4K]
The electric field generated by a proton is a radial field, so we would see the field lines going radially from the proton toward every direction. I've attached a picture representing the electric field generated by a positive charge, such as a proton, and we can see the field lines going radially from the charge toward every direction. 

3 0
3 years ago
Elements in the same periodic table group have the same___
Aliun [14]

Answer:

elements in the same periodic table group have the same valence electrons

6 0
3 years ago
When you exert 75 N on a jack to lift a 6000 N car, what is the jack’s actual mechanical advantage? Show your work.
professor190 [17]

Answer:

80

Explanation:

<em>the </em><em>mechanical</em><em> </em><em>advantage</em><em> </em><em>is </em><em>the </em><em>ratio </em><em>of </em><em>the </em><em>load </em><em>to </em><em>the </em><em>effort</em><em> </em><em>so </em><em>it </em><em>doesn't</em><em> </em><em>have </em><em>units.</em><em>t</em><em>o</em><em> </em><em>calculate</em><em> </em><em>it </em><em>you </em><em>use </em><em>the </em><em>formula</em>

<em>mechanical</em><em> advantage</em><em>=</em><em>load/</em><em>effort</em>

<em>in </em><em>this</em><em> case</em><em> </em><em>the </em><em>load </em><em>is </em><em>6</em><em>0</em><em>0</em><em>0</em><em>N</em><em> </em><em>and </em><em>the </em><em>effort</em><em> </em><em>is </em><em>7</em><em>5</em><em>N</em>

<em>Ma=</em><em>6</em><em>0</em><em>0</em><em>0</em><em>/</em><em>7</em><em>5</em>

<em>=</em><em>8</em><em>0</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

3 0
3 years ago
In a science fiction novel two enemies, Bonzo and Ender, are fighting in outer spce. From stationary positions, they push agains
Hoochie [10]

Answer:

\frac{m_B}{m_E}=1.18

Explanation:

m_B = Mass of Bonzo

m_E = Mass of Ender

u_B = Initial Velocity of Bonzo = 2.2 m/s

u_E = Initial Velocity of Ender = -2.6 m/s

From conservation of linear momentum

m_Bu_B=m_Eu_E\\\Rightarrow \frac{m_B}{m_E}=\frac{u_E}{u_B}\\\Rightarrow \frac{m_B}{m_E}=\frac{2.6}{2.2}\\\Rightarrow \frac{m_B}{m_E}=1.18

\therefore \frac{m_B}{m_E}=1.18

8 0
3 years ago
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