The power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.
<h3>Parallel force on the patient</h3>
The parallel force on the patient is calculated as follows;
F = mg sinθ
F = (75 x 9.8) x sin(12)
F = 152.82 N
<h3>Average power required </h3>
P = FV
where;
- V is speed = 3.1 km/h = 3.1/3.6 = 0.861 m/s
F = 152.82 x 0.861
F = 131.58 W
Thus, the power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.
Learn more about average power here: brainly.com/question/19415290
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The previous part of the exercise says:
"<span>Engineers are designing a system by which a falling mass m imparts kinetic energy to a rotating uniform drum to which it is attached by thin, very light wire wrapped around the rim of the drum. There is no appreciable friction in the axle of the drum, and everything starts from rest. This system is being tested on Earth, but it is to be used on Mars, where the acceleration due to gravity is 3.71 m/s². In the Earth tests, when m is set to 18.0 kg and allowed to fall through 5.50 m, it gives 300.0 J of kinetic energy to the drum."
Since Kearth = Kmars, we have, for conservation of energy, that also the potential energies must be equal:
Uearth = Umars
which means:
m </span>· gearth · hearth = m · gmars <span>· hmars
we can solve for hmars:
hmars = (gearth / gmars) </span>· hearth
= (9.8 / 3.71) · 5.50
= 14.53m
Therefore, the correct answer will be: the mass would have to fall from an height of 14.53m.
Answer:
if the stars connect to a thing, then it describes.
Answer: 5.4 kg
Explanation:"Recall that force is the result when we multiply the values of an object's mass and acceleration. Mathematically, we have
F = ma
where F is the force (in Newtons, N), m is the mass (in kilograms, kg), and a is the acceleration (in m/s²).
Since we know that the eagle was accelerating at 22.35 m/s² with a force of 120N, we can solve for the eagle's mass as shown below.
m = F/a
m = (120)/(22.35) ≈ 5.4 kg
Hence, the eagle has a mass of approximately 5.4 kg."