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barxatty [35]
2 years ago
15

The metal case of the stove gets hot when the fire is lit. Here is some information about the stove

Physics
1 answer:
Mkey [24]2 years ago
4 0

The energy required to raise the temperature of the metal case from 20°C to 70°C is 2550KJ. Details about energy can be found below.

<h3>How to calculate energy?</h3>

The energy required to raise the temperature of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

  • Q = quantity of heat energy
  • m = mass
  • c = specific heat capacity
  • ∆T = change in temperature

Q = 100 × 510 × (70 - 20)

Q = 2,550,000J

Q = 2550KJ

Therefore, the energy required to raise the temperature of the metal case from 20°C to 70°C is 2550KJ.

Learn more about energy at: brainly.com/question/1932868

#SPJ1

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This question involves the concept of the scalar product.

The magnitude of the scalar product will be "0".

<h3>SCALAR PRODUCT</h3>

The scalar product, also known as the dot product of the two vectors is given by the following formula:

A.B = |A||B|Cos\theta

where,

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5 0
2 years ago
Explain the law of conservation of mass and how it applies to balancing chemical equations
Sonja [21]
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If the mass of the object is doubled and the speed is halved then kinetic energy will change by a factor of:
Orlov [11]
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3 years ago
A ball is dropped from rest at the top of a 6.10 m
natita [175]

Answer:

n = 5 approx

Explanation:

If v be the velocity before the contact with the ground and v₁ be the velocity of bouncing back

\frac{v_1}{v} = e ( coefficient of restitution ) = \frac{1}{\sqrt{10} }

and

\frac{v_1}{v} = \sqrt{\frac{h_1}{6.1} }

h₁ is height up-to which the ball bounces back after first bounce.

From the two equations we can write that

e = \sqrt{\frac{h_1}{6.1} }

e = \sqrt{\frac{h_2}{h_1} }

So on

e^n = \sqrt{\frac{h_1}{6.1} }\times \sqrt{\frac{h_2}{h_1} }\times... \sqrt{\frac{h_n}{h_{n-1} }

(\frac{1}{\sqrt{10} })^n=\frac{2.38}{6.1}= .00396

Taking log on both sides

- n / 2 = log .00396

n / 2 = 2.4

n = 5 approx

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