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2 years ago

The metal case of the stove gets hot when the fire is lit. Here is some information about the stove

1 answer:

4 0

The energy required to raise the temperature of the metal case from 20°C to 70°C is 2550KJ. Details about energy can be found below.

<h3>How to calculate energy?</h3>

The energy required to raise the temperature of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

Q = quantity of heat energy
m = mass
c = specific heat capacity
∆T = change in temperature

Q = 100 × 510 × (70 - 20)

Q = 2,550,000J

Q = 2550KJ

Therefore, the energy required to raise the temperature of the metal case from 20°C to 70°C is 2550KJ.

Learn more about energy at: brainly.com/question/1932868

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A 23.3-kg mass is attached to one end of a horizontal spring, with the other end of the spring fixed to a wall. The mass is pull

sdas [7]

In spring mass system we know that angular frequency is given as

$\omega = 2\pi f$

f = 8.38 Hz

$\omega = 2\pi(8.38)$

$\omega = 52.65 rad/s$

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$v = A\omega$

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A = 17.5 cm

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7 0

3 years ago

This is a measure of the quantity of matter.

emmainna [20.7K]

The measure of the quantity of matter would be mass. Mass is measured in kilograms. I hope this helped!:)

3 0

3 years ago

Read 2 more answers

Using Gauss's law, calculate the electric field at a point distance s from a long wire bearing uniform charge density. i need he

11111nata11111 [884]

Answer:

E = 2k $\frac{\lambda}{ r}$

Explanation:

Gauss's law states that the electric flux equals the wax charge between the dielectric permeability.

We must define a Gaussian surface that takes advantage of the symmetry of the problem, let's use a cylinder with the faces perpendicular to the line of charge. Therefore the angle between the cylinder side area has the same direction of the electric field which is radial.

Ф = ∫ E . dA = E ∫ dA = q_{int} /ε₀

tells us that the linear charge density is

λ = q_ {int} /l

q_ {int} = l λ

we substitute

E A = l λ /ε₀

is area of cylinder is

A = 2π r l

we substitute

E = $\frac{ l \ \lambda}{ \epsilon_o \ 2\pi \ r \ l }$