fault-block mountains. hope this helps
Answer: 361° C
Explanation:
Given
Initial pressure of the gas, P1 = 294 kPa
Final pressure of the gas, P2 = 500 kPa
Initial temperature of the gas, T1 = 100° C = 100 + 273 K = 373 K
Final temperature of the gas, T2 = ?
Let us assume that the gas is an ideal gas, then we use the equation below to solve
T2/T1 = P2/P1
T2 = T1 * (P2/P1)
T2 = (100 + 273) * (500 / 294)
T2 = 373 * (500 / 294)
T2 = 373 * 1.7
T2 = 634 K
T2 = 634 K - 273 K = 361° C
Answer:
$364.29
Explanation:
given,
Packing of crates per month (u)= 800
annual carrying cost of 35 percent of the purchase price per crate.
Ordering cost(S) = $ 28
D = 800 x 12 = 9600 crates/year
H = 0.35 P
H = 0.35 x $10
H = $3.50/crate per yr.
Present Total cost
= 
= 1400 + 336
= $ 1,736



Total cost at EOQ
= 
= 685.86 + 685.85
= $ 1,371.71
the firm save annually in ordering and carrying costs by using the EOQ
= $ 1,736 - $ 1,371.71
= $364.29
C all round
Explanation:
because the outcome of a the traits would be RR, RR, Rr, Rr so it would be all round if it was Rr and Rr than there would have RR, Rr, Rr, and rr and that would have been a