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3 years ago

Under what circumstances is a moving body considered as a point object

1 answer:

4 0

Answer:An object can be considered a point object if during motion in a given time it covers a distance much greater than its own size.

Explanation:

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Your Lead Teaching Assistant is initially seated on the top of a hemispherical ice mound of radius R = 30 m. Approximate the ice

saw5 [17]

Answer:

<em>Height = 5.65 km</em>

Explanation:

$3\pi r^2$ is the circumference or we can say measures the boundary of hemisphere of friction-less ice that he is sitting on.

So, the height will be = 2 x 3.14 x (30)^2 = 5654.7 m = 5.65 km

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2 years ago

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According to the second law of thermodynamics, which is a requirement for thermal energy to flow from colder objects to hotter o

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Answer: work must be done on the system (Option A)

Explanation:

The second law of thermodynamics is the fundamental law of nature; it states that energy can be transferred from cold objects to hot objects only, if work is done on the system. If energy is added to the system then as a result the thermal energy would increase. Second law of thermodynamics is used to determine whether a process is spontaneous or not. Moreover,the second law of thermodynamics is also used in refrigerators.

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3 years ago

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Use the circuit to answer the following questions.

Zanzabum

Answer:

1)ammeter

2)ised to check measure of current flow through a circuit

3)o.90 ambere

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3 years ago

A street lamp weighs 150N. It is supported by two wires that form an angle of 120° with each other. The tensions in each wire ar

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Answer:

so you take 120÷2 wires

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2 years ago

As a glacier melts, the volume V of the ice, measured in cubic kilometers, decreases at a rate modeled by the differential equat

DaniilM [7]

Answer:

the volume in terms of time t ⇒ $\\V = e^{0.05t} + 399\\$

Explanation:

Given that :

$\frac{dv}{dt}= kv\\\\\int\limits \, \frac{dv}{v}= \int\limits \, kdt\\In v = kt + C_1\\v = e^{kt} + C\\400 = e^{k*0} + C\\400 = 1 + C\\C = 400 -1\\C = 399$

$V = e^{kt} + 399$

When v = 300 ; $\frac{dv}{dt}= - 15$

then

$\frac{dv}{dt}= kv\\\\-15 = 300*k\\\\k = \frac{-15}{300}\\\\\\k = \frac{-1}{20}\\\\k = -0.05$

∴ $\\V = e^{0.05t} + 399\\$

Therefore, the volume in terms of time t ⇒ $\\V = e^{0.05t} + 399\\$

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3 years ago

Under what circumstances is a moving body considered as a point object​

Under what circumstances is a moving body considered as a point object