Answer:
1.96g H2
Explanation:
P4 = 123.9g/mol
H2 = 2.02g/mol
*
*
*
= 1.96g H2
Describe how you would make 6.0 L of a 0.100 M KCl solution from a 4.0 M stock KCl solution.
1 answer:
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Answer:
Explanation:
Hello,
In this case, since the work done at constant pressure as in isobaric process is computed by:
Thus, given the pressure, initial volume and work, the final volume is:
Whereas the pressure must be expressed in Pa as the work is given in J (Pa*m³):
And the volumes in m³:
Thus, the final volume turns out:
Best regards.