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Pie
3 years ago
12

Steve and Jose drove Jose's car to the beach during Spring Break. The 495 kilometer drive took them 8 hours and 30 minutes. What

was their average speed for the trip?
Physics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

58.24 Km/h.

Explanation:

From the question given above, the following data were obtained:

Distance (d) = 495 Km

Time (t) = 8 h 30 mins

Speed (S) =?

Next, we shall express 8 hours 30 mins to hours.

We'll begin by convert 30 mins to hour.

60 mins = 1 h

Therefore,

30 mins = 30 mins × 1 h/ 60 mins

30 mins = 0.5 hour.

Thus,

8 h 30 min = 8 + 0.5 = 8.5 hours

Speed is define as the distance travelled per unit time. Mathematically, it is expressed as:

Speed = Distance /time

With the above formula, we can obtain the speed as shown below:

Distance (d) = 495 Km

Time (t) = 8.5 hour

Speed (S) =?

Speed = Distance /time

Speed = 495 Km / 8.5 hour

Speed = 58.24 Km/h

Thus, the speed is 58.24 Km/h.

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Becomes older

Explanation:

As sea floor spreading occurs at divergent margins, the oceanic plate becomes older. Younger plate margin are the closest to the margin whereas the older plates bushes backward away from the spreading centers.

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Sea floor spreading brainly.com/question/9912731

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A light bulb will glow when electrons flow through it. As the electron flow increases, the brightness increases as well. A stude
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Describe how thermal energy is transferred​
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A satellite of mass m is in a circular orbit of radius R2 around a spherical planet of radius R1 made of a material with density
Amiraneli [1.4K]

Answer:

a)      K = 2/3 π G m ρ R₁³ / R₂ ,  b) U = - G m M / r

Explanation:

The law of universal gravitation is

     F = G m M / r²

Part A

Let's use Newton's second law

     F = m a

The acceleration is centripetal

     a = v² / R₂

     

      G m M / R₂² = m v² / R₂

      v² = G M / R₂

They give us the density of the planet

    ρ = M / V

    V = 4/3 π R₁³

    M =   ρ V

    M =   ρ 4/3 π R₁³

    v² = 4/3 π G  ρ R₁³ / R₂

    K = ½ m v²

    K = ½ m (4/3 π G ρ R₁³ / R₂)

    K = 2/3 π G m ρ R₁³ / R₂

Part B

Potential energy and strength are related

     F = - dU / dr

     ∫ dU = - ∫ F. dr

The force was directed towards the center and the vector r outwards therefore there is an angle of 180º between the two cos 180 = -1

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    U - U₀ = G m M (- r⁻¹)

We evaluate for

    U - U₀ = -G m M (1 / r_{f} -  1 /r_{i})

They indicate that for ri = ∞     U₀ = 0

    U = - G m M / r

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We should continue to send robotic spacecrafts into space
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4 0
3 years ago
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