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alisha [4.7K]
3 years ago
8

A long straight wire carries a current of 50 A. An electron, traveling at1.0×107m/s, is 5.0 cm from the wire. What is the magnit

ude of the magnetic force on the electron if the electron velocity is directed (a) toward the wire, (b) parallel to the wire in the direction of the current, and (c) perpendicular to the two directions defined by (a) and (b)?
Physics
1 answer:
SCORPION-xisa [38]3 years ago
4 0

Answer:

Recall, The magnetic field on a electron in a wire, Bₓ = (µ₀ I)/(2πr)

Note: Magnetic force direction is at right angles to electron motion.

Magnetic force, F = q * v * Bₓ

Substituting Bₓ into F, we have

F = q * v * Bₓ = (q * v * µ₀* I)/(2π r) = (1.6 x 10⁻¹⁹ x 1.0 x 10⁷ x 4π x 10⁻⁷ x 50)/( 2π x 5 x 10⁻²) = 3.2 x 10⁻¹⁶ N

a) Hence, the magnitude of the magnetic force on the electron if the electron velocity is directed (a) toward the wire is 3.2 x 10⁻¹⁶ N  and opposite the current

b) Hence, the magnitude of the magnetic force on the electron if the electron velocity is directed (b) parallel to the wire in the direction of the current is 3.2 x 10⁻¹⁶ N  and away from the wire.

c) Hence, the magnitude of the magnetic forces on the electrons if the electron velocity is perpendicular to the two directions defined by (a) and (b) is 3.2 x 10⁻¹⁶ N  and (a) direction - opposite the current, (b) same direction as current.

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4 0
3 years ago
Read 2 more answers
WOULUJUTUL RECIPECUIUS.
3241004551 [841]

The force between the two objects is 19.73 nN.

<u>Explanation: </u>

Any force acting between two objects tends to be directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects. And this kind of attraction force between two objects is termed as gravitational force.

So if we consider M_{1} and M_{2} as the masses of both objects and let d be the distance of separation of two objects. Then the force between the two objects can be determined as below:

                      \text {Gravitational force}=\frac{G \times M_{1} \times M_{2}}{d^{2}}

As gravitational constant G=6.67 \times 10^{-11} \mathrm{m}^{3} \mathrm{kg}^{-1} \mathrm{s}^{-2}, M_{1} = 20 kg and  M_{2} = 100 kg, while d = 2.6 m, then

                    \text {Gravitational force}=\frac{6.67 \times 10^{-11} \times 20 \times 100}{(2.6)^{2}}=\frac{6.67 \times 20 \times 10^{-9}}{6.76}

Thus, we get finally,

                   \text {Gravitational force}=19.73 \times 10^{-9} \mathrm{N}

As we know, nano denoted by letter 'n' equals to 10^{-9}

So the force acting between two objects is 19.73 nN.

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