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kicyunya [14]
3 years ago
6

Write the Iconic Bond to Metals

Chemistry
1 answer:
Nutka1998 [239]3 years ago
6 0

<u>Answer:</u> The ionic compound formed is magnesium chloride having formula MgCl_2

<u>Explanation:</u>

Ionic compound is defined as the compound which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Magnesium is the 12th element of the periodic table having electronic configuration of 1s^22s^22p^63s^2

This element will loose 2 electrons to form Mg^{2+} ion

Chlorine is the 17th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^5

This element will gain 1 electron to form Cl^{-} ion

So, for every 1 atom of magnesium, 2 atoms of chlorine are required. Thus, the chemical formula becomes MgCl_2

Hence, the ionic compound formed is magnesium chloride having formula MgCl_2

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A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200
34kurt

Answer:

81 °C

Explanation:

This is a calorimetry question so a few things you will need for this. The calorimetry equation q=mcΔT & the specific heat of water (4.2J/g•°C). Other definitions are:

q = heat added/released by a sample

m = mass of sample

c=specific heat of sample

ΔT = change in temperature

from here we can rearrange the equation to state:

q/(mc) = ΔT

1200J/((20.0g)(4.2J/g•°C)) = ΔT

14°C = ΔT

If the starting temperature was 95.0°C and we know that the temperature was cooled by 14°C then the final temperature of the water would be 81.

4 0
3 years ago
How much would the temperature of 275 g of water increase if 36.5 kj of heat were added?
Andrew [12]

<u>Answer:</u> The temperature increase will be 31.70°C.

<u>Explanation:</u>

To calculate the increase in the temperature of the system, we use the equation:

q=mc\Delta T

where,

q = Heat absorbed = 36.5 kJ = 36500J

m = Mass of water = 275 g

c = Specific heat capacity of water = 4.186J/g^oC

\Delta T = change in temperature = ? °C

Putting values in above equation, we get:

36500J=275\times 4.186J/g^oC\times \Delta T\\\\\Delta T=31.70^oC

Hence, the temperature increase will be 31.70°C.

8 0
3 years ago
Read 2 more answers
For a reaction:
torisob [31]

Looking at the equation .look at the moles noted below

  • Ca(OH)_2=1mol
  • NH_2Cl=2mol.
  • CaCL_2=1mol
  • NH_2=2mol
  • H_20=2mol.

#a

There is 2 moles of NH2Cl.

  • Hence limiting reagent is Ca(OH)_2

#2

Moles at reactant=3

Moles at product=5

Moles left:-

\\ \sf\longmapsto 5-3=2mol

#d

\\ \sf\longmapsto pV=nRT

\\ \sf\longmapsto 1.5V=2(8.3)(27)

\\ \sf\longmapsto 1.5V=448.2

\\ \sf\longmapsto V=\dfrac{448.2}{1.5}

\\ \sf\longmapsto V=298.8mL

7 0
3 years ago
Classify these salts as acidic, basic, or neutral. KCL, NH4Br, K2CO3, NaCN, LiClO4? This is what I put but got it wrong: KCl = b
MaRussiya [10]
In classifying salts as neutral, acidic, or basic, it is important to take note of the strength of the acids and bases that they come from. A strong acid and strong base produce a neutral salt. A weak acid and strong base produce a basic salt. A strong acid and weak base produce an acidic salt. So the answers must be:

KCl = neutral (from HCl and KOH)
NH4Br = acidic (from NH4 and HBr)
K2CO3 = basic (from KOH and H2CO3)
NaCN = basic (from NaOH and HCN)
LiClO = basic (from LiOH and HClO)
3 0
4 years ago
Read 2 more answers
On a hot summer day, a piece of ice is removed from a cooler and placed in a cup that is sitting on a picnic table. Which of the
dlinn [17]
The ice absorbs heat from the cup . And the ice loses its composition thus melting .
5 0
3 years ago
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