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kipiarov [429]
3 years ago
14

1. What elements are carbohydrates generally composed of?

Chemistry
2 answers:
Nataly_w [17]3 years ago
7 0
The answer is hydrogen,oxygen,and carbon
Llana [10]3 years ago
4 0
The correct answer is  hydrogen<span>, and </span>oxygen<span>. </span>
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Zora wants to dissolve a solute in a solvent quickly. Which best describes what she should do?
lesya692 [45]

Answer:

C    shake it repeatedly

Explanation:

i think thats the answer if not sorry hope it helps you.

4 0
2 years ago
If you have 5 unknowns and they were secondary alcohol aldehyde, carboxylic acid, amine, and alkane Put plan to identify the unk
Finger [1]

Answer:

the unknowns

Explanation:

7 0
2 years ago
Which of the following sample will have the greatest average speed at 355 K?. A. CH4. B. Ne. C. C2H4. D. Cl2
Amanda [17]

Answer:

The correct option is methane :CH_4.

Explanation:

Average speed of the gas molecules id given by expression:

v_{avg}=\sqrt{\frac{8kT}{\pi m}}

k = Boltzmann cosnatnt

T = Temperature of the gas molecules = 355 K

m = molecular mass of the molecule

v_{avg}\propto \sqrt{\frac{1}{m}}

Molar mass of methane = 18 g/mol

Molar mass of neon = 20.18 g/mol

Molar mass of ethene = 28 g/mol

Molar mass of chlorine gas = 70 g/mol

Lower the value of molar mass of gas molecule higher will be the average speed.So, from the given options methane gas greatest average seed because it has lowest molecular mass

6 0
3 years ago
Read 2 more answers
Consider the following reaction: CH3OH(g)⇌CO(g)+2H2(g) Part A Calculate ΔG for this reaction at 25 ∘C under the following condit
kati45 [8]

<u>Answer:</u> The \Delta G of the reaction at given temperature is -12.964 kJ/mol.

<u>Explanation:</u>

For the given chemical reaction:

CH_3OH(g)\rightleftharpoons CO(g)+2H_2(g)

The expression of K_p for the given reaction:

K_p=\frac{(p_{CO})\times (p_{H_2}^2)}{p_{CH_3OH}}

We are given:

p_{CO}=0.140atm\\p_{H_2}=0.180atm\\p_{CH_3OH}=0.850atm

Putting values in above equation, we get:

K_p=\frac{(0.140)\times (0.180)^2}{0.850}\\\\K_p=5.34\times 10^{-3}

To calculate the Gibbs free energy of the reaction, we use the equation:

\Delta G=\Delta G^o+RT\ln K_p

where,

\Delta G = Gibbs' free energy of the reaction = ?

\Delta G^o = Standard gibbs' free energy change of the reaction = 0 J (at equilibrium)

R = Gas constant = 8.314J/K mol

T = Temperature = 25^oC=[25+273]K=298K

K_p = equilibrium constant in terms of partial pressure = 5.34\times 10^{-3}

Putting values in above equation, we get:

\Delta G=0+(8.314J/K.mol\times 298K\times \ln(5.34\times 10^{-3}))\\\\\Delta G=-12963.96J/mol=-12.964kJ/mol

Hence, the \Delta G of the reaction at given temperature is -12.964 kJ/mol.

5 0
3 years ago
PLEASE HELP ASAP
V125BC [204]

Answer:

third one

Explanation:

5 0
3 years ago
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