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kipiarov [429]
3 years ago
14

1. What elements are carbohydrates generally composed of?

Chemistry
2 answers:
Nataly_w [17]3 years ago
7 0
The answer is hydrogen,oxygen,and carbon
Llana [10]3 years ago
4 0
The correct answer is  hydrogen<span>, and </span>oxygen<span>. </span>
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Calculate the volume of a 0.5M solution containing 20g of NaOH
Tju [1.3M]

Answer:

1L

Explanation:

First, let us calculate the number of mole present in 20g of NaOH. This is illustrated below:

Mass = 20g

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

Number of mole =?

Number of mole = Mass /Molar Mass

Number of mole of NaOH = 20/40 = 0.5mol

From the question given, we obtained the following data:

Molarity = 0.5M

Mole = 0.5mole

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.5/0.5

Volume = 1L

6 0
3 years ago
Read 2 more answers
Given the balanced equation representing a reaction:
dimaraw [331]
The answer is (4) synthesis. Synthesis reaction means that two or more reactants combine directly to one production. Substitution or single replacement means that one element of a compound is replaced by another element. Double replacement means that two ionic reactants exchange ions to form two new productions.
3 0
3 years ago
How to balance Mg3n2+H20&gt;&gt;Mg(oh)2+Nh3?
alexandr1967 [171]
Mg₃N₂ + 6H₂O  =  3Mg(OH)₂ + 2NH₃
4 0
3 years ago
I have a question about ionization energy.
ValentinkaMS [17]
Ionization energy is the measure of the extend to which the nucleus attracts the outermost electron
if ionization energy us high than force of attraction Is high so it is not easy to remove and vice versa .
hope you understand.....
5 0
3 years ago
Suppose 2.8 moles of methane are allowed to react with 5 moles of oxygen.
Ronch [10]

Answer : The limiting reagent is O_2

Solution : Given,

Moles of methane = 2.8 moles

Moles of O_2 = 5 moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 5 moles of O_2 react with \frac{5}{2}=2.5 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Hence, the limiting reagent is O_2

8 0
3 years ago
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