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3 years ago

12

Which of the following types of stars are dim but can have high surface temperatures?

1 answer:

exis [7]3 years ago

8 0

The answer is A,because a red giant star

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A 100 Ohm, 200 Ohm, and 400 Ohm resistors are in parallel with each other. What is the equivalent

krok68 [10]

Answer:

1/R = 1/R1 + 1/R2 + 1/R3

1/1 + 1/2 + 1/4 = 1 + .5 + .25 = 1.75

1/1.75 = .572

multiplying this by 100 gives us

R = 57.2 ohms

The smallest resistor (100 ohms) will draw the most current

(One can also use R = R1 R2 R3 / (R1 R2 + R1 R3 + R2 R3)

7 0

2 years ago

Read 2 more answers

A bicyclist makes a trip that consists of three parts, each in the same direction (due north) along a straight road. During the

Advocard [28]

Answer:

a

The total distance traveled is $D = 26760 \ m$

b

The average velocity is $v_{avg} = 6.8 \ m/s$

Explanation:

From the question we are told that

The time taken for first part $t_1 = 22 \ minutes = 22*60 = 1320 \ s$

The speed for the first part is $v_1 = 7.2 \ m/s$

The time taken for second part is $t_2 = 36 \ minutes = 2160 \ s$

The speed for the second part is $v_2 = 5.1 \ m/s$

The time taken for third part is $t_3 = 8 \ minutes = 480 \ s$

The speed for the third part is $v_3 = 13 m/s$

Generally

$distance(D) = velocity * time$

Therefore the total distance traveled is

$D = (v_1 * t_1) + (v_2 * t_2 ) + (v_3 * t_3)$

substituting values

$D = (7.2 * 1320) + (5.1 * 2160) + (13 * 480)$

$D = 26760 \ m$

Generally the average velocity is mathematically represented as

$v_{avg} = \frac{D}{t_{total}}$

Where $t_{total}$ is the total time taken which is mathematically represented as

$t_{total} = 1320 + 2160 + 480$

$t_{total} =3960\ s$

The average velocity is

$v_{avg} = \frac{26760}{3960}$

$v_{avg} = 6.8 \ m/s$

8 0

3 years ago

A woman drives a 45 gram golf ball off of a tee and gives the ball a velocity of 28 m/s to the right. What is the change in mome

lidiya [134]

Answer:

1.26

Explanation:

change 45 grams to kilograms which is 0.045 then just multiply it by 28 m/s

0.045x28=1.260

7 0

2 years ago

An electric field of intensity 3.25 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.

jekas [21]

Answer:

$\varphi_1= 796.25 N m^2/C$

$\varphi_2= 0 N m^2/C$

$\varphi_3=686.1 N m^2/C$

Explanation:

From the question we are told that

Electric field of intensity $E= 3.25 kN/C$

Rectangle parameter Width $W=0.350 m$ Length $L=0.700 m$

Angle to the normal $\angle=30.5 \textdegree$

Generally the equation for Electric flux at parallel to the yz plane $\varphi_1$ is mathematically given by

$\varphi_1=EA cos theta$

$\varphi_1=3.25* 10^3 N/C * ( 0.350)(0.700) cos 0$

$\varphi_1= 796.25 N m^2/C$

Generally the equation for Electric flux at parallel to xy plane $\varphi_2$ is mathematically given by

$\varphi_2=EA cos theta$

$\varphi_2=3.25* 10^3 N/C * ( 0.350)(0.700) cos 90$

$\varphi_2= 0 N m^2/C$

Generally the equation for Electric flux at angle 30 to x plane $\varphi_3$ is mathematically given by

$\varphi_3=EA cos theta$

$\varphi_3=3.25* 10^3 N/C * ( 0.350)(0.700) cos 30.5$

$\varphi_3=686.072219 N m^2/C$

$\varphi_3=686.1 N m^2/C$

7 0

3 years ago

A pogo stick has a spring with a force constant of 2.50 × 104 N/m , which can be compressed 11.2 cm. what maximum height, in met

AleksandrR [38]

Answer:

h = 36.4 cm

Explanation:

given,

spring constant = 2.5 x 10⁴ N/m

compressed distance = 11.2 cm = 0.112 m

mass of the child = 44 kg

maximum height = ?

by energy of conservation

$K.E_i +P.E_i= K.E_f + P.E_f$

$\dfrac{1}{2}kx^2 = mgh$

$\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h$

$\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h$

$156.8 = 44 \times 9.8 \times h$

$h = \dfrac{156.8}{44 \times 9.8}$

h = 0.364 m

h = 36.4 cm

7 0

3 years ago