Which illustrates projectile motion?

"Ryan drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Ryan drove

Flura [38]

Answer:

Distance between Ryan home and mountain will be 252 miles

Explanation:

Let the distance from home to mountains is d

It is given that it took 7 hours to go mountains from home

Let the speed in going to mountain is v

Then according to question speed in coming from mountain is v+27

And time taken in come from mountain to home is hour

As distance will be same in both case

Distance will be equal to $distance=speed\times time$

So $v\times 7=(v+27)\times 4$

$3v=108$

v = 36 miles per hour

So distance will be equal to $d=36\times 7=252miles$

8 0

4 years ago

Match the term and the definition

sineoko [7]

Answer:

1. When a cold air mass and a warm air mass meet but are at a standstill, the boundary is called stationary front.

2. If warm or more humid air presses forward and colder or drier air draws back, the boundary is called warm front.

3. If colder or drier air presses forward and warmer or more humid air draws back, the boundary is called cold front.

4. Sometimes a warm air mass can get caught between two cold fronts, which can force the warm air up into a wedge shape is called occluded front.

3 0

3 years ago

A 51.0 kg cheetah accelerates from rest to its top speed of 31.7 m/s. HINT (a) How much net work (in J) is required for the chee

andrey2020 [161]

(a) $2.56\cdot 10^4 J$

The work-energy theorem states that the work done on the cheetah is equal to its change in kinetic energy:

$W= \Delta K = \frac{1}{2}mv^2 - \frac{1}{2}mu^2$

where

m = 51.0 kg is the mass of the cheetah

u = 0 is the initial speed of the cheetah (zero because it starts from rest)

u = 31.7 m/s is the final speed

Substituting, we find

$W=\frac{1}{2}(51.0 kg)(31.7 m/s)^2 - \frac{1}{2}(51.0 kg)(0)^2=2.56\cdot 10^4 J$

(b) 6.1 cal

The conversion between calories and Joules is

1 cal = 4186 J

Here the energy the cheetah needs is

$E=2.56\cdot 10^4 J$

Therefore we can set up a simple proportion

$1 cal : 4186 J = x : 2.56\cdot 10^4 J$

to find the equivalent energy in calories:

$x=\frac{(1 cal)(2.56\cdot 10^4 J)}{4186 J}=6.1 cal$

3 0

3 years ago

Why did scientists using classical, Newtonian physics have difficulty explaining the photoelectric effect?

alexandr402 [8]

Classical physics considered light to behave as a wave in all environments; it had a set amplitude, frequency etc. The problem was that this meant that there was a continuous variation in its properties, hence if the amplitude of the light was incresed by a bit, a phenomenon like the phhotoelectric one would become only marginally more apparent. However, in this case, there is a cutoff point which means that the only-wave theory had to be wrong.

3 0

3 years ago

Read 2 more answers

Divers found two substances on the bottom of the ocean. At room temperature, both substances are liquid. Scientists then transfe

shtirl [24]

They have different melting points

3 0

3 years ago

Read 2 more answers