Question

I need help solving my homework problem , can somebody help me please . This class is physics two . My question is “ where the potential difference across ab is 49.5 V “ ?

Answer 1

Explanation:

a) $Q_{Total} = C_{eq}V = (3.5\:\mu \text{F})(49.5V) = 1.73×10^{-4}\:\text{C}$

b) The individual capacitors in series circuit carry the same amount of charge as the $Q_{Total}$ so

$Q_{10} = Q_{Total} = 1.73×10^{-4}\:\text{C}$

c) Likewise, $C_9$ will carry the same amount of charge as $C_{10}$