Answer:
true
Explanation:
as long as it is the right conductive material
This is the answer to what a hypothesis may also be called
Distance (s)=100m
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v=

we get
V₁=

V₁=10m/s
V₂=

V₂=9.8m/s
V₃=

V₃=9.61 m/s
V₄=

V₄=9.43 m/s
V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43
Well let's see:
A). No. A capacitor doesn't measure anything.
B). No. The power delivered to the circuit is determined by
the battery or power supply and all the things in
the circuit that dissipate energy. A capacitor doesn't
do any of these things.
C). No. If any current actually flows between its plates,
the capacitor is shot and can't do its job, and
must be replaced.
D). Yes. A capacitor stores charges on its plates, and
electrical energy in the field between its plates.
<em>Answer: </em>
tim e (t) = 20 min.
= 20 × 60 = 1200 s ,
Work ( W) = 4560000 J
= 4560 KJ ,
Determine:
Power output (P) = Work ÷ time
= 4560 ÷ 1200
<em> P = 3.8 KW</em>