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MaRussiya [10]
3 years ago
6

If the price of gasoline at a particular station in Europe is 5 euros per liter. An American student in Europe is allowed to use

40 euros to buy gasoline. Knowing that 4 quarts make a gallon, and that 1 liter is about 1 US liquid quart, about how many gallons can the student buy?
Physics
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

Number of gallons =2 gallon

Explanation:

given data:

rate of gasoline ineurope = 5 euro per liter

total money to buy gasoline =  40 euro

total gasoline an american can buy in europe = \frac{40}{5}

= 8 litres of gasoline

As given in the question 1 ltr is 1 quarts therefore  

Total no. of quarts is 8 quarts

As from question 4 quarts is equal to one gallon, hence

Number of gallons= \frac{8}{4} = 2 gallon

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Les propriétés de l’air?
crimeas [40]

Answer:

Lorsque l'on détend l'air son volume augmente et sa pression diminue. L'air qui est un mélange de gaz est compressible et expansible. – Lorsque l'on comprime l'air, son volume diminue et sa pression augmente. – Lorsque l'on détend l'air, son volume augmente et sa pression diminue.

4 0
2 years ago
Which items are matter?
Mumz [18]
Without being provided a list of items, I would have to generally say that everything around you is matter. There are a few exceptions to this list, but a general rule of thumb is anything you can touch, taste, smell or hold would be considered matter. Sound, light, time (Dr. Who may disagree) and heat would be considered non-matter items. 
3 0
3 years ago
A series RLC circuit has a resonant frequency = 6.00 kHz. When it is driven at a frequency = 8.00 kHz, it has an
ANEK [815]

The resistance (R) of the circuit is 707.1 ohms and the inductance (L) is 0.032 H.

<h3>Resistance of the circuit</h3>

For the phase constant of 45⁰, impedance is equal to the resistance of the circuit.

Z= R\sqrt{2} \\\\R  = \frac{Z}{\sqrt{2} } \\\\R = \frac{1000}{\sqrt{2} } = 707.1 \ ohms

<h3>Resonant frequency</h3>

f = \frac{1}{2\pi \sqrt{LC} } \\\\6000 = \frac{1}{2\pi \sqrt{LC} } \\\\2\pi(6000) = \frac{1}{\sqrt{LC} } \\\\\sqrt{LC} = \frac{1}{2\pi (6000)} \\\\LC = (\frac{1}{2\pi (6000)})^2\\\\LC = 7.034 \times 10^{-10} \\\\ C = \frac{7.034 \times 10^{-10} }{L} ---(1)

<h3>At driven frequency</h3>

X_l- X_c = R\\\\\omega L - \frac{1}{\omega C}  = 707.1\\\\2\pi f L -  \frac{1}{2\pi fC} = 707.1\\\\2\pi (8000) L - \frac{1}{2\pi (8000) C } = 707.1\ \ --(2)\\\\

<em>solve 1 and 2 together</em>

2\pi(8000) L - \frac{L}{2\pi (8000)(7.034 \times 10^{-10})} = 707.1\\\\50272L - 28279.48L = 707.1\\\\L = 0.032 \ H

Learn more about impedance of RLC circuit here: brainly.com/question/372577

7 0
2 years ago
A person standing on the surface of the earth has a weight of 650 N. What is its weight at a distance of two earth radii from th
snow_lady [41]

Answer:

72.22 N

Explanation:

F = weight

m = mass of body

M = mass of earth

R = radius of earth

G = universal constant of gravitation

F_1= 650 N

F_1 = GMm/R^2

two earth radius above the surface of the earth:

F_2=  GMm/(3R)^2=  GMm/9R^2= F_1/9= 650/9

=72.22 N

4 0
3 years ago
An object is placed 50cm in front of a concave mirror of radius 60cm. How far from the mirror is the image?
Shkiper50 [21]

Answer:To explian the exact calculation of this pruduct we must not try!

3 0
3 years ago
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