First, we calculate the mass of Phosphorous present:
283.88 x 0.4364
= 123.88 amu
Atomic mass of P is 31 amu
moles of P = mass / Ar
= 123.88 / 31
= 4.0 moles
We know that one mole of substance has 6.02 x 10²³ particles
Atoms of P = 4 x 6.02 x 10²³
= 2.41 x 10²⁴ atoms
Answer:
Explanation:
4/1=4
3/2=1.5
2/3=0.666667
1/4=0.25
D has the least number so its D
I think this happens because during melting or boiling at constant temperature, the entropy dramatically increases because energy is removed from the system during the change. Entropy increases with increase in temperature, entropy increases steadily with increasing temperature up to the melting point of the solid, where the entropy increases further due to addition of freedom of molecules which increases the randomness of the substance. At boiling point of liquid, another abrupt increase in entropy occurs, this results from increased volume available to the atoms or molecules as they enter the gaseous state.
Answer:
2*10^9electrons
Explanation:
Remember that the net force will be zero at terminal voltege so
Mg = 6πrng
At 35v
We have
qvr = 6πrng
q= 6 x 3.142* nx 2.6*10^-5/35
q,= 3.2x 10^ - 10C
So using n= q/e
= 3.2x 10^ - 10C/1.6*10-19
= 2*10^9electrons
