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harkovskaia [24]
3 years ago
6

Why do some metals loose their shine overtime but gold does not?

Chemistry
1 answer:
aivan3 [116]3 years ago
5 0
Becuase gold is very unreactive and does not react with oxygen whereas other metals do, therefore they tarnish and gold does not
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Se requieren preparar 1500 ml de una solución al 55% en masa de hidróxido de calcio, sabiendo que la densidad de dicha solución
Masja [62]

Respuesta:

968 g Ca(OH)₂

Explicación:

Paso 1: Calcular la masa de solución

Tenemos 1500 mL de una solución cuya densidad es 1.17 g/mL, es decir, 1 mL de solución tiene una masa de 1.17 g.

1500 mL × 1.17 g/mL = 1.76 × 10³ g

Paso 2: Calcular la masa de hidróxido de calcio en 1.76 × 10³ g de solución

La solución tiene una concentración de 55% en masa de hidróxido de calcio, es decir, cada 100 gramos de solución hay 55 gramos de hidróxido de calcio.

1.76 × 10³ g Solución × 55 g Ca(OH)₂/100 g Solución = 968 g Ca(OH)₂

6 0
2 years ago
What would you need to do to calculate the molality of 10 g of NaCl in 2 kg of
jasenka [17]

Answer:

O B. Convert the 10 g of NaCl to moles of NaCl.

Explanation:

The formula for finding the molality is m=moles of solute/kg of solvent. The solute for this question is NaCl and the solvent is water.

(10g NaCl)(1 mol NaCl/58.44g NaCl)=0.1711 mol NaCl

58.44 is the molar mass of NaCl

m=0.1711 mol NaCl/2 kg H2O

m=0.085557837

7 0
3 years ago
A block of metal has a volume of 14.0in3 and weighs 5.26lb .
natulia [17]
Mass of block, m = 5.26 lb  
1 lb = 453.592 g
 5.26 lb = 2385.896 g
V = 14 in3
 1 in = 2.5 cm
 1 in3 = 15.625 cm3
 14 in3 = 218.75 cm3


Density = mass/volume
 = 2358.896 / 218.75
 = 10.783 g/cm3
6 0
3 years ago
Read 2 more answers
Some hypothetical alloy is composed of 12. 5 wt% of metal a and 87. 5 wt% of metal b. If the densities of metals a and b are 4.
gavmur [86]

Answer:

The number of

atoms in the unit cell is 2

Explanation:

7 0
2 years ago
How many kL does a 9.51 ´ 109 cL sample contain?
elena-14-01-66 [18.8K]

Answer:

9.51 × 10⁴ kL

Explanation:

Step 1: Given data

Volume of the sample (V): 9.51 × 10⁹ cL

Step 2: Convert "V" to liters

We will use the conversion factor 1 L = 100 cL.

9.51 × 10⁹ cL × (1 L / 100 cL) = 9.51 × 10⁷ L

Step 3: Convert "V" to kL

We will use the conversion factor 1 kL = 1000 L.

9.51 × 10⁷ L × (1 kL / 1000 L) = 9.51 × 10⁴ kL

9.51 × 10⁹ cL is equal to 9.51 × 10⁴ kL.

4 0
3 years ago
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