1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeka57 [31]
3 years ago
9

There are two machines for sale that you are considering purchasing for your sawmill to produce hardwood flooring. You want to f

ind the one that has a higher process capability index, or Cpk. The goal is to produce flooring that is between 46 and 50 millimeters thick. The first machine is more accurate on average, producing to a mean of 48 millimeters…but unfortunately it has more variation with a standard deviation of .7 millimeters. The second machine is not as accurate, with a mean of 47mm, but does deliver a more consistent output, with standard deviation of .3mm.
Engineering
1 answer:
devlian [24]3 years ago
4 0

Answer:

Machine 2 has a higher process capability index, it would be best considered for purchase.

Explanation:

Process capability index: Cpk= Min [(mean-L spec)/3sd; (U spec-mean)/3sd]

For machine 1, mean= 48mm and L spec= 46 and U spec= 50, Standard deviation sd= 0.7

Cpk= [0.952;0.952]= 0.952

For machine 2, mean= 47 and L spec= 46 and U spec= 50, Standard deviation sd= 0.3

Cpk= [1.111;3.333]= 1.111

It is clearly observed from the calculations above that the Cpk value of machine 2 is higher than that of machine 1.

Since machine 2 has a higher process capability index, it would be best considered for purchase.

You might be interested in
A type 3 wind turbine has rated wind speed of 13 m/s. Coefficient of performance of this turbine is 0.3. Calculate the rated pow
Anna [14]

Answer:

Rated power = 1345.66 W/m²

Mechanical power developed = 3169035.1875 W

Explanation:

Wind speed, V = 13 m/s

Coefficient of performance of turbine, C_p = 0.3

Rotor diameter, d = 100 m

or

Radius = 50 m

Air density, ρ = 1.225 kg/m³

Now,

Rated power = \frac{1}{2}\rho V^3

or

Rated power = \frac{1}{2}\times1.225\times13^3

or

Rated power = 1345.66 W/m²

b) Mechanical power developed =  \frac{1}{2}\rho AV^3C_p

Here, A is the area of the rotor

or

A = π × 50²

thus,

Mechanical power developed = \frac{1}{2}\times1.225\times\pi\times50^2\times13^3\times0.3

or

Mechanical power developed =  3169035.1875 W

8 0
2 years ago
Your new mobile phone business is now approaching its first anniversary and you are able to step back and finally take a deep br
Leya [2.2K]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

7 0
2 years ago
Answer the following questions, and very briefly explain your answer:
alexandr1967 [171]

Answer:

A) micro defects are left behind on the surface of metal components during the manufacturing process. These defects, in the form of micro-cracks or pits, becomes initiation sites for crack propagation or corrosion. Removing these imperfections on the surface of metal parts by electroplating greatly improves the life of metal components.

B) it will reduce fatigue crack growth.

Dispersion hardening involves the inclusion of small, hard particles in the metal, thus restricting the movement of dislocations, and thereby raising the strength properties. In dispersion hardening it is assumed that the precipitates do not deform with the matrix and that a moving dislocation bypasses the obstacles (precipitates) by moving in the clean pieces of crystal between the precipitated particles.

C) stress concentrations such as changes in section with sharp corners caused yielding, which will typically occur first at a stress concentration. For ductile materials localised plastic deformation can cause a redistribution of stress, enabling the component to continue to carry load. Brittle materials will typically fail at the stress concentration. Repeated loading may cause a fatigue crack to initiate and slowly grow at a stress concentration leading to the failure of even ductile materials. Fatigue cracks always start at stress raisers, so removing such defects increases the fatigue strength.

5 0
2 years ago
The fan blades suddenly experience an angular acceleration of 2 rad/s2. If the blades are rotating with an initial angular veloc
madreJ [45]

Answer:

Option B

116 ft/s^{2}

Explanation:

\theta=2 rev=2(2\pi)=4\pi

\alpha \theta=0.5(\omega_f^{2}-\omega_i^{2})

\alpha (4\pi)= 0.5(\omega_f^{2}-\omega_i^{2})

\alpha (8\pi)= (\omega_f^{2}-\omega_i^{2})

(2) (8\pi)= (\omega_f^{2}-\omega_i^{2})

(2) (8\pi)= (\omega_f^{2}-4^{2})

\omega_f=8.14 rads/s

v=r\omega=1.75*8.14=14.245 ft/s

Centripetal acceleration =\omega_f^{2} r=8.14^{2}*1.75=115.95 ft/s^{2}

Tangential component=dr=2*1.75=3.5

Resultant=\sqrt{3.5^{2}+115.95^{2}}\approx 116 ft/s^{2}

5 0
3 years ago
Radioactive wastes are temporarily stored in a spherical container, the center of which is buried a distance of 10 m below the e
a_sh-v [17]

Answer:

Outside temperature =88.03°C

Explanation:

Conductivity of air-soil from standard table

   K=0.60 W/m-k

To find temperature we need to balance energy

Heat generation=Heat dissipation

Now find the value

We know that for sphere

q=\dfrac{2\pi DK}{1-\dfrac{D}{4H}}(T_1-T_2)

Given that q=500 W

so

500=\dfrac{2\pi 2\times .6}{1-\dfrac{2}{4\times 10}}(T_1-25)

By solving that equation we get

T_2=88.03°C

So outside temperature =88.03°C

6 0
3 years ago
Other questions:
  • What is the capacity of the machine in batches?
    10·1 answer
  • In case of damaged prestressed concrete I girders which are used for restoring strength?
    9·1 answer
  • An R-134a refrigeration system is operating with an evaporator pressure of 200 kPa. The refrigerant is 10% in vapor phase at the
    15·1 answer
  • How will the proposed study contribute to your career?*<br>(quantity Surveying​
    11·1 answer
  • 4.7 If the maximum tensile force in any of the truss members must be limited to 22 kN, and the maximum compressive force must be
    9·1 answer
  • When does someone's work on the Internet become copyrighted?
    15·1 answer
  • Which of the following describes what a manufacturing engineer does
    9·2 answers
  • What building codes did Mega Corporation fail to follow?
    9·1 answer
  • What invention of the Middle Ages contributed to making books easily available?
    15·1 answer
  • What is the creative process that helps you overcome writer's block called?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!