Answer:
1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻
2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)
Explanation:
Main reaction: 2Ag⁺(aq) + Mn(s) ⇄ 2Ag(s) + Mn²⁺(aq)
In the oxidation half reaction, the oxidation number increases:
Mn changes from 0, in the ground state to Mn²⁺.
The reduction half reaction occurs where the element decrease the oxidation number, because it is gaining electrons.
Silver changes from Ag⁺ to Ag.
1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻
2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)
To balance the hole reaction, we need to multiply by 2, the second half reaction:
Mn(s) ⇄ Mn²⁺(aq) + 2e⁻
(Ag⁺(aq) + 1e⁻ ⇄ Ag(s)) . 2
2Ag⁺(aq) + 2e⁻ ⇄ 2Ag(s)
Now we sum, and we can cancel the electrons:
2Ag⁺(aq) + Mn(s) + 2e⁻ ⇄ 2Ag(s) + Mn²⁺(aq) + 2e⁻
The answer is B) gain 8 electrons
Answer:
A. The children will be more likely to survive than if they did not have the trait.
Explanation:
Process of elimination
B. It will not affect the children.
Cannot be true, if it didn't impact the children then how would survival of the fittest work?
D. The children will be able to adapt if the environment changes.
That just... not how adapting works when it comes to evolution.
C. The children will be more likely to survive than their parents were
Everyone has the same trait, everyone is equal in that regard.
A. The children will be more likely to survive than if they did not have the trait.
"Suppose a pair of animals has a trait that helps them survive in their environment." The trait helps them survive. Not having the trait makes them less likely to survive. A is correct
Answer:
2. Co(NO3)2 + H2
Explanation:
Hello,
In this case, we are evidencing a simple displacement reaction wherein the cobalt is able displace the hydrogen to produce cobalt (II) nitrate and gaseous hydrogen as a result of cobalt's higher activity:

Therefore, answer is 2. Co(NO3)2 + H2.
Best regards.
Solution: (a) The net force is zero because car is travelling with same speed that is 60 miles per hour or there is no acceleration.
(b) Mass of object is 10 kg
Acceleration is 2 m/s², thus force can be calculated as follows:
F=m×a
Here, m is mass of object and a is its acceleration thus,
F=10 kg×2 m/s²
=20 kg m/s²
Here, 1 N=1 kg m/s²
Thus, F=20 N
(c) Force on object is 17 N and its acceleration is 1.5 m/s².
Mass of the object can be calculated as follows:
m=\frac{F}{a}
thus,
m=\frac{17 N}{1.5 m/s^{2}}=11.33 (\frac{N}{m/s^{2}})
Here, 1 N=1 kg m/s²
Thus,
m=11.33 kg