7.42 moles of Ag(PO4)2 x 297.8109g / 1 moles = 2210g Ag(PO4)2
Answer:
15.52 kj
Explanation:
H2 O mole wt ~ 18 gm
6.35 gm is 6.35 gm /18 gm/mole = .353 moles of H2O
.353 moles * 44 kj/mole =
Answer:
V₂ = 0.95 L
Explanation:
Given data:
Initial temperature of gas = 171.4 K
Final temperature of gas = 288.4 K
Final volume = 1.6 L
Initial volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₁ = V₂T₁ /T₂
V₂ = 1.6 L × 171.4 K / 288.4 k
V₂ = 274.24 L.K / 288.4 K
V₂ = 0.95 L
