Answer:
Empirical formula = C₃S₂
Explanation:
Given data:
Mass of carbon = 44.0 mg (44/1000 = 0.044 g)
Mass of sulfur = 122 mg - 44.0 mg = 78 mg = 78/1000 = 0.078 g)
Empirical formula = ?
Solution:
First of all we will calculate the number of moles.
Number of moles of carbon = mass / molar mass
Number of moles of carbon = 0.044 g/ 12.01 g/mol
Number of moles of carbon = 0.0037 mol
Number of moles of sulfur:
Number of moles = mass / molar mass
Number of moles = 0.078 g/ 32,066 g/mol
Number of moles = 0.0024 mol
Now we will compare the moles:
C : S
0.0037/0.0024 : 0.0024/0.0024
1.5 : 1
C : S = 2(1.5 : 1)
C : S = 3 : 2
Empirical formula = C₃S₂
Answer:
NaF(aq)
Explanation:
When sodium bromide react with fluorine sodium fluoride is formed. Florine is more reactive than bromine that's why it displace the bromine and form compound with sodium.
Chemical reaction:
NaBr(aq) + F₂(aq) → NaF(aq) + Br₂(aq)
Balanced chemical equation:
2NaBr(aq) + F₂(aq) → 2NaF(aq) + Br₂(aq)
Sodium is alkali metal and have one valance electron. It loses one electron and show +1 charge. While all halogen elements need one electron to complete the octet and show -1 charge.
That's why one halogen atom is combine with one sodium atom to make overall compound neutral.
Answer:
2.0 x 10⁻³ M/s.
Explanation:
- The rate of the reaction is the change of the concentration of the reactants or the products with time.
<em>The rate of the reaction = - Δ[reactants]/Δt = - [(0.6 M - 1.8 M)]/(580 s - 0 s) = 2.069 x 10⁻³ M/s.</em>
Answer:
The no. of protons = atomic number
please rate 5 stars
