Answer:The compound is paramagnetic. It has four unpaired electrons b) the compound will be green in colour. Ammonium pentaflourido aqua Iron II. Iron has a d-electron configuration of d4
Explanation: Weak field ligands cause weak crystal field splitting leading to the formation of paramagnetic species. Most iron II compounds appear green in colour. In naming ligands, negative ions are named first followed by neutral species. Iron has an outermost electron configuration of 3d4s2 so Fe II is a d4 ion
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Iron (II) oxide is composed of iron with an oxidation number of +2 (shown by the II after iron) and an oxygen that has an oxidation number of -2 (oxygen almost always has an oxidation state of -2). Since the anion and cation both have a charge of +or- 2, they bond with each other with a 1 to 1 ratio and the formula should be FeO
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Hydrogen should be your final answer.
Answer:
Explanation:
We will need a balanced chemical equation with masses, moles, and molar masses.
1. Gather all the information in one place:
M_r: 2.016 17.03
3H₂ + N₂ ⟶ 2NH₃
m/g: 6.33 × 10⁻⁴
2. Calculate the moles of H₂
3. Calculate the moles of NH₃
The molar ratio is 2 mol NH₃/3 mol H₂.
4. Calculate the molecules of NH₃
There are 6.022 × 10²³ molecules of NH₃/1 mol NH₃.