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FinnZ [79.3K]
3 years ago
6

4. Which of the following usually occurs with a short circuit? A. Most of the current will flow through one part of the circuit.

B. All parts of the circuit will begin to carry higher amounts of current than normal. C. All parts of the circuit will begin to carry lower amounts of current than normal. D. The material within a fuse may begin to melt when the current ceases to exist.
Physics
2 answers:
Svetllana [295]3 years ago
6 0
<span>A. Most of the current will flow through one part of the circuit. </span>
ira [324]3 years ago
4 0
A is the correct answer :)
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It is difficult to walk on a smooth floor why​
quester [9]

Answer:

because theres is not enough friction so it will be super slippery

Explanation:

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2 years ago
Define one solar day​
Mila [183]

Answer:

the time between successive meridian transits of the sum at a particular place

8 0
2 years ago
5) A parallel series electric blasting circuit consists of 6 branches of 8 caps each. Cap legwire length is 28 ft. The cap circu
andrezito [222]

Answer:

Minimum DC current = 9 Ampere

Voltage = 74.862 V

Explanation:

Here in this questions three resistors are used in series

Resistance of cap circuit

R_1 =\frac{ 8* 2.3}{6} \\R_1 = 3.067

Here 2.3 is the resistance per cap

Resistance of bus wire

R_2 = \frac{50 * 4.02 }{1000} \\R_2 = 0.201

Where 4.02 is the resistance per 1000 feet of bus wire of gauge 16

Resistance of firing line

R_3 = \frac{(2*1000)* 2.525}{1000} \\R_3 = 5.05

where 2.525 is the resistance per 1000 feet of bus wire of gauge 14

Total resistance is equal to

R = R_1 + R_2 + R_3\\R = 3.067 + 0.201 + 5.05 \\R = 8.318

Current in firing line is equal to

1.5 * 6\\= 9

Voltage is equal to product of resistance and current

= 9 * 8.318\\= 74.862

4 0
2 years ago
Which of the following would have an effect on an object's mass?
ICE Princess25 [194]
None of the above

mass is measurement of how much stuff in inside something.
if you freeze or heat an object, you merely change the state of the object. the mass is conserved.
if you change the elevation, nothing happens to the mass. the stuff will not leave the object.
so it is None of the above


8 0
2 years ago
You hang different masses M from the lower end of a vertical spring and measure the period T for each value of M. You use Excel
goblinko [34]

We the Period T we can find the constant k,

That is

T = 2 \pi \sqrt{\frac{m}{k}}

We delete the squart root elevating squareing everything,

T^2=\frac{4\pi^2}{k}M +\frac{4\pi^2}{k}m_{spring}

M is the hanging mass, m is the spring mass,

k is the spring constant and T the time period

a) So for the equation we can compare, that is,

y=T^2=0.0569x+0.0010

Here x is the hanging mass M, so comparing the equation we know that

\frac{4\pi^2}{k}=0.0569\\k= \frac{4\pi^2}{0.0569}\\k=693.821N/m

b) For the mass of the spring we make similar process, so comparing,

\frac{4\pi^2}{k}m =0.001\\m=\frac{0.004k}{4\pi^2} =\frac{0.001*693.821}{4\pi^2}\\m=0.0175kg\\m=17.5g

6 0
2 years ago
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