Answer:
Load carried by shaft=9.92 ft-lb
Explanation:
Given: Power P=4.4 HP
P=3281.08 W
<u><em>Power: </em></u>Rate of change of work with respect to time is called power.
We know that P=
rad/sec
So that P=
So 3281.08=
T=13.45 N-m (1 N-m=0.737 ft-lb)
So T=9.92 ft-lb.
Load carried by shaft=9.92 ft-lb
1) 
2) 8.418
Explanation:
1)
The two components of the velocity field in x and y for the field in this problem are:


The x-component and y-component of the acceleration field can be found using the following equations:


The derivatives in this problem are:






Substituting, we find:

And

2)
In this part of the problem, we want to find the acceleration at the point
(x,y) = (-1,5)
So we have
x = -1
y = 5
First of all, we substitute these values of x and y into the expression for the components of the acceleration field:

And so we find:

And finally, we find the magnitude of the acceleration simply by applying Pythagorean's theorem:

The guy above me is right fyi and its not 50 points
Answer:
1. Manpower Management
2. Productive Meetings
3.Establish administrative policies, procedures, and standards.
4. High command over assets management.
5. Specific field related knowledge of procurement.
6. Compliance and EHS knowledge.
Explanation: