Explanation :
The balanced chemical reaction is,

The expression for the rates of consumption of the reactants are:
The rate of consumption of
= ![-\frac{1}{5}\frac{d[Br^-]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B5%7D%5Cfrac%7Bd%5BBr%5E-%5D%7D%7Bdt%7D)
The rate of consumption of
= ![-\frac{d[BrO_3^-]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BBrO_3%5E-%5D%7D%7Bdt%7D)
The rate of consumption of
= ![\frac{1}{6}\frac{d[H^+]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D)
The expression for the rates of formation of the products are:
The rate of consumption of
= ![+\frac{1}{3}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=%2B%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
The rate of consumption of
= ![+\frac{1}{3}\frac{d[H_2O]}{dt}](https://tex.z-dn.net/?f=%2B%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BH_2O%5D%7D%7Bdt%7D)
Answer:
A) Fission
Explanation:
Fission is the splitting of a heavy, unstable nucleus into two lighter nuclei, and fusion is the process where two light nuclei combine together releasing vast amounts of energy.
I believe the correct answer from the choices listed above is option C. The type of substances that has <span>chemical bonds that are not directional and valence electrons that move freely between the atoms are metals. Hope this answers the question. Have a nice day.</span>
Answer:
6.15.3 k
Explanation:
From the question we can see that
q = 0, Δu = w
Then,

putting values wet
=
T_f = 615.3 K