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3 years ago

If a fluorine atom and nitrogen atom combine to form a compound, what type of bond will they form

Chemistry

1 answer:

dmitriy555 [2]3 years ago

4 0

Answer:

I guess covalent bond is formed

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A) What is the maximum number of grams of nickel bromide that can be produced from the reaction of 67.8 g of nickel with 37.3 g

svetoff [14.1K]

Answer:

The answer to your question is a) 51.07 g of NiBr₂ b) Nickel, 54 g

Explanation:

Data

mass of NiBr₂ = ?

mass if Ni = 67.8 g

mass of Br = 37.3 g

Balanced chemical reaction

Ni + Br₂ ⇒ NiBr₂

Process

1.- Find the atomic mass of the reactants and the molar mass of the product

Ni = 59 g

Br = 79.9 x 2 = 159.8 g

NiBr₂ = 59 + 159.8 = 218.8 g

2.- Find the limiting reactant

theoretical yield Ni/Br₂ = 59/159.8 = 0.369

experimental yield Ni/Br₂ = 67.8/37.3 = 1.81

The limiting reactant is Bromine because the experimental yield was lower than the theoretical yield.

3.- Calculate the mass of NiBr₂

159.8 g of Br₂ --------------- 218.8 g of NiBr₂

37.3 g of Br₂ -------------- x

x = (37.3 x 218.8) / 159.8

x = 8161.24/159.8

x = 51.07 g of NiBr₂

4.- Find the excess reactant

The excess reactant is Nickel

59 g of Ni ---------------- 159.8 g of Br₂

x ---------------- 37.3 g of Br₂

x = (37.3 x 59)/159.8

x = 2200.7/159.8

x = 13.77 g of Ni

Excess Ni = 67.8 - 13.77

= 54 g

5 0

3 years ago

Explain why some atoms gain or lose electrons to form ions.

anygoal [31]

Because some atoms are more stable when they gain or lose an electron and form ions.

7 0

3 years ago

Read 2 more answers

Please help me I really need help

Mars2501 [29]

Answer:

Explanation:

chemically changed

hope it helps!!

8 0

3 years ago

Read 2 more answers

A 25 gram(m) metal ball is heated to 200C(delta T) with 2330 Joules(q) of energy. What is the specific heat of the metal?

Dominik [7]

Answer:

The specific heat of the metal is 0.466 $\frac{J}{g*C}$

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

Q= 2330 J
c= ?
m= 25 g
ΔT= 200 °C

Replacing:

2330 J= c*25 g* 200 °C

Solving:

$c=\frac{2330 J}{25 g* 200 C}$

c=0.466 $\frac{J}{g*C}$

The specific heat of the metal is 0.466 $\frac{J}{g*C}$

6 0

3 years ago

Read 2 more answers

What percentage of radioactive substance remains after two half-lives

Ksju [112]

Answer:

After 2 half-lives there will be 25% of the original isotope, and 75% of the decay product. After 3 half-lives there will be 12.5% of the original isotope, and 87.5% of the decay product. After 4 half-lives there will be 6.25% of the original isotope, and 93.75% of the decay product.

Explanation:

3 0

3 years ago