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amm1812
3 years ago
8

In many problems where the potential energy is considered between two objects, the potential energy is defined as zero when the

particles are in infinite distance apart. Using the definition of potential energy, explain why the potential energy would be positive if the force between the particles is repulsive and negative if the force between the particles is attractive for noninfinite distances.
Engineering
1 answer:
algol [13]3 years ago
4 0

Answer:

potential energy=ε Qq/r. Putting values of charge along with sign and calculating the potential energy will tell whether the resultant force is attractive or repulsive.

Explanation:

potential energy=ε Qq/r

q and Q are charges on each particle

So in case the particles have attractive force between them, one particle will be negative and the other will be positiive. The result will be negative.

In case the particles have repulsive forces, the charge on both particles will be either positive or negative. The result will be positive

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Answer:

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Explanation:

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6 0
3 years ago
Determine (a) the principal stresses and (b) the maximum in-plane shear stress and average normal stress at the point. Specify t
raketka [301]

Answer:

a) 53 MPa,  14.87 degree

b) 60.5 MPa  

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Explanation:

Given

A = 45

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a) stress P1 = (A+B)/2 + Sqrt ({(A-B)/2}^2 + C)

Substituting the given values, we get -

P1 = (45-60)/2 + Sqrt ({(45-(-60))/2}^2 + 30)

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Likewise P2 = (A+B)/2 - Sqrt ({(A-B)/2}^2 + C)

Substituting the given values, we get -

P1 = (45-60)/2 - Sqrt ({(45-(-60))/2}^2 + 30)

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a = 14.87 degree

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b) Shear stress in plane

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5 0
3 years ago
Write a C++ program to display yearly calendar. You need to use the array defined below in your program. // the first number is
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Answer:

//Annual calendar

#include <iostream>

#include <string>

#include <iomanip>

void month(int numDays, int day)

{

int i;

string weekDays[] = {"Su", "Mo", "Tu", "We", "Th", "Fr", "Sa"};

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{

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      for(int i=1; i< firstDay; i++)

          cout << left << setw(1) << "|" << setw(2) << " ";

      int cellCnt = 0;

      // Iteration of days

      for(int i=1; i<=numDays; i++)

      {

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          cout << left << setw(1) << "|" << setw(2) << i;

          cellCnt += 1;

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          if ((i + firstDay-1) % 7 == 0)

          {

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              cellCnt = 0;

          }

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      if (cellCnt != 0)

      {

          // For printing spaces

          for(int i=1; i<7-cellCnt+2; i++)

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{

int i, day=1;

int yearly[12][2] = {{1,31},{2,28},{3,31},{4,30},{5,31},{6,30},{7,31},{8,31},{9,30},{10,31},{11,30},{12,31}};

string months[] = {"January",

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"March",

"April",

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"June",

"July",

"August",

"September",

"October",

"November",

"December"};

for(i=0; i<12; i++)

{

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else

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day = day + 1;

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cout << "\n";

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return 0;

}

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Answer:

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