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Anit [1.1K]
2 years ago
12

The end of a large tubular workpart is to be faced on a NC vertical boring mill. The part has an outside diameter of 38.0 in and

inside diameter of 24.0 in. If the facing operation is performed at a rotational speed = 40 rev/min, feed = 0.015 in/rev, and depth = 0.180 in, determine: (a) the cutting time to complete the facing operation, (b) the cutting speeds and metal removal rates at the beginning and end of the cut.

Engineering
1 answer:
nata0808 [166]2 years ago
5 0

Answer:

(a) the cutting time to complete the facing operation = 11.667mins

b) the cutting speeds and metal removal rates at the beginning= 12.89in³/min and end of the cut. = 8.143in³/min

Explanation:

check attached files below for answer.

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I think will help
7 0
3 years ago
Write the implementation (.cpp file) of the Player class from the previous exercise. Again, the class contains:
hoa [83]

Answer:

//Define the header file

#ifndef PLAYER_H

#define PLAYER_H

//header file.

#include <string>

//Use the standard namespace.

using namespace std;

//Define the class Player.

class Player

{

//Declare the required data members.

string name;

int score;

public:

//Declare the required

//member functions.

void setName(string par_name);

void setScore(int par_score);

string getName();

int getScore();    

}

//End the definition

//of the header file.

#endif

Player.cpp:

//Include the "Player.h" header file,

#include "Player.h"

//Define the setName() function.

void Player::setName(string par_name)

{

name = par_name;

}

//Define the setScore() function.

void Player::setScore(int par_score)

{

score = par_score;

}

//Define the getName() function.

string Player::getName()

{

return name;

}

//Define the getScore() function.

int Player::getScore()

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return score;

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7 0
3 years ago
A 25-W compact fluorescent lightbulb (CFL) produces the light equivalent of a 100-W incandescent bulb. The population of North A
wariber [46]

Answer:

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8 0
3 years ago
The Reynolds number is a dimensionless group defined for a fluid flowing in a pipe as Re Durho/μ whereD is pipe diameter, u is f
Gala2k [10]

Answer:

the flow is turbulent

Explanation:

The Reynolds number is given by

Re=ρVD/μ

where

V=fluid speed=0.48ft/s=0.146m/s

D=diameter=2.067in=0.0525m

ρ=density=0.805g/cm^3=805Kg/m^3

μ=0.43Cp=4.3x10^-4Pas

Re=(805)(0.146)(0.0525)/4.3x10^-4=14349.59

Re>2100  the flow is turbulent

Note: if you do not want to use a calculator you can use the graphs to calculate the Reynolds number according to their properties

8 0
2 years ago
Atmospheric air at a pressure of 1 atm and dry bulb temperature of 28 C has a wet-bulb temperature of 20 C.
IrinaK [193]

Answer:

a) \phi = 48\%, b) \omega = 0.012\,\frac{kg\,H_{2}O}{kg\,Air}, c) h = 58\,\frac{kJ}{kg\,Air}, d) T = 17^{\textdegree}C, e) P_{v} = 1.831\,kPa

Explanation:

a) The relative humidity is given by the intersection of the dry bulb and wet bulb temperatures:

\phi = 48\%

b) The humidity ratio is:

\omega = 0.012\,\frac{kg\,H_{2}O}{kg\,Air}

c) The enthalpy is:

h = 58\,\frac{kJ}{kg\,Air}

d) The dew-point temperature is:

T = 17^{\textdegree}C

e) The water vapor pressure is the product of the relative humidity and the saturation pressure evaluated at dry bulb temperature:

P_{v} = \phi \cdot P_{sat}

P_{v} = 0.48\cdot (3.816\,kPa)

P_{v} = 1.831\,kPa

7 0
2 years ago
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