Answer:
as slated in your solution, if delay time is 2.30 mins, hence 9 vehicle will be on queue as the improved service commenced.
Explanation:
4 vehicle per min, in 2 mins of the delay time 8 vehicles while in 0.3 min average of 1 vehicle join the queue. making 9 vehicle maximum
Answer:
load = 156 lb/ft
Explanation:
given data
interior wall of a building = 2×4 wood studs
plastered = 1 side
wall height = 13 ft
solution
we get here load so first we get wood stud load and that is
we know here from ASCE-7 norm
dead load of 2 x 4 wood studs with 1 side plaster = 12 psf
and we have given height 13 ft
so load will be = 12 psf × 13 ft
load = 156 lb/ft
Answer:
The mass of car in slug =108.5 slug.
The mass of car in kilogram =1575 Kg.
Explanation:
Given that
Mass of car = 3500 lbs
We know that
1 lbs =0.031 slug
So
3500 lbs = 0.031 x 3500 slug
So the mass of car in slug =108.5 slug.
We know that
1 lbs =0.45 kilograms
so
3500 lbs = 3500 x 0.45 Kg
So the mass of car in kilogram =1575 Kg.
Answer:
The velocities in points A and B are 1.9 and 7.63 m/s respectively. The Pressure at point B is 28 Kpa.
Explanation:
Assuming the fluid to be incompressible we can apply for the continuity equation for fluids:
Where A, V and Q are the areas, velocities and volume rate respectively. For section A and B the areas are:
Using the volume rate:
Assuming no losses, the energy equation for fluids can be written as:
Here P, V, p, z and g represent the pressure, velocities, height and gravity acceleration. Considering the zero height level at point A and solving for Pb:
Knowing the manometric pressure in point A of 70kPa, the height at point B of 1.5 meters, the density of water of 1000 kg/m^3 and the velocities calculated, the pressure at B results:
Answer:
Percentage of solution=32. 96%
Explanation:
Given that initially tank have 50% solution.It means that amount of solution=0.5 x 2500 =1250 lts
Lets take the amount of solution at time t = A
So
Now by integration
Where C is the constant
Given that at t=0 ,A=1250
So
When t=20 min
A=837.90
So percentage of solution after 20 min
Percentage of solution=32. 96%