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Amiraneli [1.4K]
3 years ago
12

explaining how Newton’s Three Laws of Motion relate to the marshmallow catapult. AND DONT JUST PUT ANYTHING OR I WILL ERASE YOUR

COMMENT! THANK YOU
Physics
1 answer:
Vaselesa [24]3 years ago
6 0
As to the third law every object has an equal and opposite reaction. therefore the the stone is forwarded as a result of the force applied. as to the first law, an object in motion will move at uniform velocities because of the unbalanced force. As to 2nd law, the acceleration is directly proportioal to magnitude of the net force. therefore the more force you apply from the catapault, the further it will go.'
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An ideal parallel-plate capacitor consists of a set of two parallel plates of area A separated by a very small distance d. When
sleet_krkn [62]

Answer:

2dQ²/2εA = 2U₀

Explanation:

The energy stored in the ideal parallel plate capacitor U = Q²/2C. For a parallel plate capacitor, C = εA/d where A is the area between the plates and D is the distance between them. So

U = Q²/2C = Q²/2εA/d = dQ²/2εA. At distance d₁ = d, U = U₀,

U₀ = dQ²/2εA,

When d₂ = 2d, U₁ = d₂Q²/2εA = 2dQ²/2εA = 2U₀

3 0
3 years ago
Which description correctly summarizes how an electric motor causes an axle to turn?
Tasya [4]

Answer:

The poles of the magnetic field generated around the armature are attracted to the opposite poles of the permanent magnet. As the opposite poles align, the commutator reverses the current direction so like poles are aligned and the armature continues to spin.

Explanation:

3 0
3 years ago
Choices are 10.7<br> 16.9<br> 15.2<br> 17.5
madreJ [45]

Answer:

D

Explanation:

correct me if I'm wrong on your answer and it's the right answer from my son

6 0
2 years ago
A projectile is launched horizontally from a 20-m tall edifice with a vox of 25 m/s. How long will it take for the projectile to
NISA [10]

Answer:

a) First let's analyze the vertical problem:

When the projectile is on the air, the only vertical force acting on it is the gravitational force, then the acceleration of the projectile is the gravitational acceleration, and we can write this as:

a(t) = -9.8m/s^2

To get the vertical velocity we need to integrate over time to get:

v(t) = (-9.8m/s^2)*t + v0

where v0 is the initial vertical velocity because the object is thrown horizontally, we do not have any initial vertical velocity, then v0 = 0m/s

v(t) = (-9.8m/s^2)*t

To get the vertical position equation we need to integrate over time again, to get:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + p0

where p0 is the initial position, in this case is the height of the edifice, 20m

then:

p(t) = (-4.9m/s^2)*t^2+ 20m

The projectile will hit the ground when p(t) = 0m, then we need to solve:

(-4.9m/s^2)*t^2+ 20m = 0m

20m = (4.9m/s^2)*t^2

√(20m/ (4.9m/s^2)) = t = 2.02 seconds

The correct option is a.

b) The range will be the total horizontal distance traveled by the projectile, as we do not have any horizontal force, we know that the horizontal velocity is 25 m/s constant.

Now we can use the relationship:

distance = speed*time

We know that the projectile travels for 2.02 seconds, then the total distance that it travels is:

distance = 2.02s*25m/s = 50.5m

Here the correct option is a.

c) Again, the horizontal velocity never changes, is 25m/s constantly, then here the correct option is option b. 25m/s

d) Here we need to evaluate the velocity equation in t = 2.02 seconds, this is the velocity of the projectile when it hits the ground.

v(2.02s) =  (-9.8m/s^2)*2.02s = -19.796 m/s

The velocity is negative because it goes down, and it matches with option d, so I suppose that the correct option here is option d (because the sign depends on how you think the problem)

4 0
3 years ago
When the temperature of the air is 25 degress C, the velocity of a sound wave traveling through the air is approximately
dusya [7]
Assuming an ideal gas, the speed of sound depends on temperature 
only.   Air is almost an ideal gas. 

Assuming the temperature of 25°C in a "standard atmosphere", the 
density of air is 1.1644 kg/m3, and the speed of sound is 346.13 m/s. 

The velocity can't be specified, since the question gives no information 
regarding the direction of the sound.
6 0
3 years ago
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