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1 year ago

Which of the following is correct concerning the uncontrolled burn phase?

Physics

1 answer:

beks73 [17]1 year ago

7 0

The option that is the correct one concerning the uncontrolled burn phase is:

The uncontrolled burn phase is characterized by uncontrolled combustion in a cylinder until fuel accumulated during ignition delay is burned.

<h3>What is uncontrolled combustion?</h3>

Uncontrolled Combustion is known to be the the time and place in which a kind of an ignition will stop and it is said to be never fixed by anything in regards to the compression ignition engine as seen in SI engines.

Note that the four Stages of combustion are:

1. Pre-flame combustion

2. Uncontrolled combustion

3. Controlled combustion and

4. After burning

Hence, The uncontrolled burn phase is characterized by uncontrolled combustion in a cylinder until fuel accumulated during ignition delay is burned as all the fuel need to burn out.

Learn more about burn phase from

brainly.com/question/14414049

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3 years ago

An ice skater is spinning at 6.00 rev/s with his moment of inertia being 0.400 kg/m2. Calculate his new moment of inertia if he

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Answer:

New moment of inertia will be $I=1.92kgm^2$

Explanation:

It is given initially angular velocity $\omega =6rev/sec=6\times 2\pi =37.68rad/sec$

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3 years ago

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Travka [436]

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The correct answer is option C

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2 years ago

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Answer:

The angle between the emergent blue and red light is $0.566^{o}$

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Thus for blue incident light we have

$1\times sin(40.05)=1.641\times sin(\theta _{rb})\\\\\therefore \theta _{rb}=sin^{-1}(\frac{sin(40.05)}{1.64})\\\\\theta _{rb}=23.10$

Similarly using the same procedure for red light we have

$1\times sin(40.05)=1.603\times sin(\theta _{rr})\\\\\therefore \theta _{rr}=sin^{-1}(\frac{sin(40.05)}{1.603})\\\\\theta _{rr}=23.66^{o}$

Thus the absolute value of angle between the refracted blue and red light is

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3 years ago