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2 years ago

10

A diatomic molecule of Nitrogen (N) would be held by covalent bonds.

2 answers:

zzz [600]2 years ago

3 0

Yes that would be true

Varvara68 [4.7K]2 years ago

3 0

Answer:

True

Explanation:

Nitrogen has five valence electrons, therefore, it needs three more valence electrons to complete its octet. In a diatomic molecule of Nitrogen, each atom shares three electrons to the bond, that is, three pairs of electrons are shared between the two atoms. This is called a triple bond, which is a covalent bond.

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What did Rutherford’s model of the atom include that Thomson’s model did not have?

Ksivusya [100]

Rutherford overturned Thomson's model in 1911 with his well-known gold foil experiment in which he demonstrated that the atom has a tiny and heavy nucleus. Rutherford designed an experiment to use the alpha particles emitted by a radioactive element as probes to the unseen world of atomic structure.

3 0

2 years ago

What is the force of a lead ball that starts with a momentum of 7 kg*m/s and end with a momentum of 22 kg*m/s over a time of 31

Gwar [14]

Answer:

F = 0.483 N

Explanation:

Initial momentum, $P_i= 7\ kg-m/s$

Final momentum, $P_f= 22\ kg-m/s$

Time, t = 31 s

We need to find the force of a lead ball. We can use here the impulse momentum theorem.

$\text{Change in momentum}=F\times t$

F is force

$P_f-P_i=Ft\\\\F=\dfrac{P_f-P_i}{t}\\\\F=\dfrac{22-7}{31}\\\\F=0.483\ N$

So, the force is 0.483 N.

6 0

2 years ago

Find acceleration. Will give brainliest!

zalisa [80]

Answer:

16200 km/s

270 km/min

4.5 km/h

Explanation:

Acceleration Formula: Average Acceleration = Δv/Δt (change in velocity over change in time)

Simply plug in our known variables and solve:

a = (45.0 - 0)/10

a = 45.0/10

a = 4.5 km/h

7 0

2 years ago

Read 2 more answers

PLEASE HELP ME WITH THIS ONE QUESTION

adoni [48]

Answer:

B) R1 = 6 V and R2 = 6V

Explanation:

In series, both resistors will carry the same current.

that current will be I = V/R = 12 / (10 + 10) = 0.6 A

The voltage drop across each resistor is V = IR = 0.6(10) = 6 V

6 0

3 years ago

a cylinder has a radius of 2.1cm and a length of 8.8cm .total charge 6.1 x 10^-7C is distributed uniformly throughout. the volum

7nadin3 [17]

The answer for the following problem is explained below.

Therefore the volume charge density of a substance (ρ) is 0.04 × $10^{-1}$ C.

Explanation:

Given:

radius (r) =2.1 cm = 2.1 × $10^{-2}$ m

height (h) =8.8 cm = 8.8 × $10^{-2}$ m

total charge (q) =6.1× $10^{-7}$ C

To solve:

volume charge density (ρ)

We know;

<u> ρ =q ÷ v</u>

volume of cylinder = π ×r × r × h

volume of cylinder =3.14 × 2.1 × 2.1 × $10^{-4}$ × 8.8 × $10^{-2}$

volume of cylinder (v) = 122.23 × $10^{-6}$

<u> ρ =q ÷ v</u>

ρ = 6.1× $10^{-7}$ ÷ 122.23 × $10^{-6}$

<u>ρ = 0.04 × </u> $10^{-1}$ <u> C</u>

Therefore the volume charge density of a substance (ρ) is 0.04 × $10^{-1}$ C.

3 0

3 years ago