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Stella [2.4K]
3 years ago
9

According to Charles's law, for a fixed quantity of gas at constant pressure, which of the given quantities is constant? Accordi

ng to Charles's law, for a fixed quantity of gas at constant pressure, which of the given quantities is constant?
a)V/T

b)V*T

c)V+T

Physics
2 answers:
grandymaker [24]3 years ago
8 0

Option (a) is correct as the Charles law states that for a fixed quantity of gas at constant pressure,  the quantity \fbox{\begin\\V/T\end{minispace}} will be constant.

Further explanation:

The ideal gas is a hypothetical gas whose atoms or molecules occupy very negligible space and  obeys the gas law. It is assumed that the ideal gas has no interaction with other molecules of gas.

Given:

The pressure of the gas is constant, p={\text{constant}}.

The mass of the gas is constant, m={\text{constant}}.

Concept:

The ideal gas equation is given by the expression given below:

pV=nRT                                             …… (1)

Here, p is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant  and T is the absolute temperature.

The ideal gas equation is based on the following assumption:

1. There are no attractive or repulsive forces between the particles.

2. The average kinetic energy of the gas particles is proportional to temperature.

3. Pressure is caused due to collision between the gas molecules and the walls of the container.

The Charles law states that if the pressure of a gas is held constant, the volume of gas is directly  proportional to the absolute temperature of the gas.

The expression for the Charles law is:

\fbox{\begin\\V\propto T\end{minispace}}                                                                                   ...... (2)

Rearrange the equation (1).

\dfrac{V}{T} = \dfrac{{nR}}{p}

The number of moles of the gas, n, and the universal gas constant, R, is constant for a gas. Therefore, the left hand side of the above equation i.e., nR/p will also be a constant.

Therefore, we can write:

\fbox{\begin\\\text{V/T }={\text{constant}}\end{minispace}}

Thus, option (a) is correct as the Charles law states that for a fixed quantity of gas at constant  pressure, the quantity \fbox{\begin\\V/T\end{minispace}} will be constant.

Option (b) is incorrect as the quantity \dfrac{{nR}}{p} is constant which is equal to \dfrac{V}{T}.

Option (c) is incorrect as V and T both varies linearly if pressure is held constant so the quantity V + T  is not constant.

Learn more:

1.  The motion of a body under friction brainly.com/question/4033012

2.  A ball falling under the acceleration due to gravity brainly.com/question/10934170

3. Conservation of energy brainly.com/question/3943029

Answer Details:

Grade: College

Subject: Physics

Chapter: Thermodynamics

Keywords:

Charles’s law, fixed quantity, constant pressure, V/T, V x T, V+T, V is directly proportional T, ideal gas  equation, interaction, molecule, gas law, hypothetical gas, nR/p, number of moles, temperature.

Naddik [55]3 years ago
7 0
Charles's <span>law is also known as the law of volumes explained the relation between the volume of gas and its temperature.

Charles's law states that: " At constant pressure, the volume of a certain mass of gas is directly proportional to its temperature in kelvin".
This means that:
V = T*constant
V/T = constant

Based on this, the correct choice is:
</span><span>a) V/T</span>
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(b) τ = 18.79 Nm

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(a)

First we find the torque due to the ball in hand:

τ₁ = F₁d₁

where,

τ₁ = Torque due to ball in hand = ?

F₁ = Force due to ball in hand = m₁g = (3 kg)(9.8 m/s²) = 29.4 N

d₁ = perpendicular distance between ball and shoulder = 60 cm = 0.6 m

τ₁ = (29.4 N)(0.6 m)

τ₁ = 17.64 Nm

Now, we calculate the torque due to the his arm:

τ₁ = F₁d₁

where,

τ₂ = Torque due to arm = ?

F₂ = Force due to arm = m₂g = (3.8 kg)(9.8 m/s²) = 37.24 N

d₂ = perpendicular distance between center of mass and shoulder = 40% of 60 cm = (0.4)(60 cm) = 24 cm = 0.24 m

τ₂ = (37.24 N)(0.24 m)

τ₂ = 8.94 Nm

Since, both torques have same direction. Therefore, total torque will be:

τ = τ₁ + τ₂

τ = 17.64 Nm + 8.94 Nm

<u>τ = 26.58 Nm</u>

<u></u>

(b)

Now, the arm is at 45° below horizontal line.

First we find the torque due to the ball in hand:

τ₁ = F₁d₁

where,

τ₁ = Torque due to ball in hand = ?

F₁ = Force due to ball in hand = m₁g = (3 kg)(9.8 m/s²) = 29.4 N

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τ₁ = (29.4 N)(0.4242 m)

τ₁ = 12.47 Nm

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τ₁ = F₁d₁

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τ₂ = (37.24 N)(0.1696 m)

τ₂ = 6.32 Nm

Since, both torques have same direction. Therefore, total torque will be:

τ = τ₁ + τ₂

τ = 12.47 Nm + 6.32 Nm

<u>τ = 18.79 Nm</u>

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